2

我正在尝试订购查询，但没有得到想要的结果：

SELECT R.[Name] AS Project, ISNULL(P.[Name]+' - '+P.[Description], 'KanBan') AS Sprint, S.[Number] AS Story, T.[Name] AS Task,
   sum(CASE WHEN DatePart(dw, D.ActivityDate) = 1 THEN D.[Hours] ELSE 0 END) AS Monday,
   sum(CASE WHEN DatePart(dw, D.ActivityDate) = 2 THEN D.[Hours] ELSE 0 END) AS Tuesday,
   sum(CASE WHEN DatePart(dw, D.ActivityDate) = 3 THEN D.[Hours] ELSE 0 END) AS Wednesday,
   sum(CASE WHEN DatePart(dw, D.ActivityDate) = 4 THEN D.[Hours] ELSE 0 END) AS Thursday,
   sum(CASE WHEN DatePart(dw, D.ActivityDate) = 5 THEN D.[Hours] ELSE 0 END) AS Friday,
   sum(CASE WHEN DatePart(dw, D.ActivityDate) = 6 THEN D.[Hours] ELSE 0 END) AS Saturday,
   sum(CASE WHEN DatePart(dw, D.ActivityDate) = 7 THEN D.[Hours] ELSE 0 END) AS Sunday
FROM DailyTaskHours D
INNER JOIN Task T ON D.TaskId = T.PK_Task 
INNER JOIN Story S ON T.StoryId = S.PK_Story 
LEFT JOIN Sprint P ON S.SprintId = P.PK_Sprint 
INNER JOIN Product R ON S.ProductId = R.PK_Product
GROUP BY R.[Name], P.[Name], P.[Description], S.[Number], T.[Name]
ORDER BY CASE WHEN (P.[Name]+' - '+P.[Description]) = 'KanBan' then 1 else 0 end, Project ASC, Story ASC, Task ASC

首先，我想要 P.[Name]+' - '+P.[Description] 为 NULL 并用 'KanBan' 填充到底部，然后按产品字母顺序排列，然后按产品 Sprint ，然后是故事，然后是任务。

我怎样才能做到这一点？

编辑：谢谢这里是最后的查询：

SELECT R.[Name] AS Project, ISNULL(P.[Name]+' - '+P.[Description], 'KanBan') AS Sprint, S.[Number] AS Story, T.[Name] AS Task,
   sum(CASE WHEN DatePart(dw, D.ActivityDate) = 1 THEN D.[Hours] ELSE 0 END) AS Monday,
   sum(CASE WHEN DatePart(dw, D.ActivityDate) = 2 THEN D.[Hours] ELSE 0 END) AS Tuesday,
   sum(CASE WHEN DatePart(dw, D.ActivityDate) = 3 THEN D.[Hours] ELSE 0 END) AS Wednesday,
   sum(CASE WHEN DatePart(dw, D.ActivityDate) = 4 THEN D.[Hours] ELSE 0 END) AS Thursday,
   sum(CASE WHEN DatePart(dw, D.ActivityDate) = 5 THEN D.[Hours] ELSE 0 END) AS Friday,
   sum(CASE WHEN DatePart(dw, D.ActivityDate) = 6 THEN D.[Hours] ELSE 0 END) AS Saturday,
   sum(CASE WHEN DatePart(dw, D.ActivityDate) = 7 THEN D.[Hours] ELSE 0 END) AS Sunday
FROM DailyTaskHours D
INNER JOIN Task T ON D.TaskId = T.PK_Task 
INNER JOIN Story S ON T.StoryId = S.PK_Story 
LEFT JOIN Sprint P ON S.SprintId = P.PK_Sprint 
INNER JOIN Product R ON S.ProductId = R.PK_Product
GROUP BY R.[Name], P.[Name], P.[Description], S.[Number], T.[Name]
ORDER BY CASE WHEN ISNULL(P.[Name]+' - '+P.[Description], 'KanBan') = 'KanBan'
    THEN 1
    ELSE 0 END,
    Project ASC,
    Sprint ASC,
    Story ASC,
    Task ASC
4

2 回答 2

2

只需要稍微修改一下：

ORDER BY CASE WHEN ISNULL(P.[Name]+' - '+P.[Description], 'KanBan') = 'KanBan'
    THEN 0
    ELSE 1 END

问题是你永远不会进入KanBan你的ORDER BY条款。

于 2013-09-17T14:39:20.153 回答
1

这可能看起来有点令人费解，但我认为这是最能说明问题的方法：

; WITH cte AS (
  <put your query here>
)
SELECT list
     , of
     , columns
     , including
     , the
     , kanban
     , one
FROM   cte
ORDER
    BY CASE WHEN sprint = 'KanBan' THEN 937 ELSE -937 END ASC
     , Product
     , Sprint
     , story
     , task
于 2013-09-17T14:46:06.727 回答