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编辑：感谢 Ipmcc，他在评论中给了我一个解决方案。

我想使用 memset 将一个四字节地址分配到我动态分配的前四个内存字节中。下面显示了一个带有我想要做的评论的示例。我所有试图找出如何做到这一点或自己弄清楚的尝试都以失败告终。

任何帮助将不胜感激，谢谢。

int main(void)
{
  // Define and assign eight bytes of memory
  unsigned char *data1 = new unsigned char [8];
  unsigned char *data2 = new unsigned char [8];

  // Set all eight bytes in both data1 and data2 to 0x00
  memset(data1, 0x00, 8);
  memset(data2, 0x00, 8);

  // Lets say that the address of *data1 is: 00508d30
  // Lets say that the address of *data2 is: 0050b180

  // I want to set the first four bytes in data1 to the
  // address of data2, so it would look something like this...
  memset(data1, 0x00, 1); ++data1;
  memset(data1, 0x50, 1); ++data1;
  memset(data1, 0xB1, 1); ++data1;
  memset(data1, 0x80, 1);
  data1 -= 3; // Reset pointer

  // But of course this is in no way practical or viable
  // since the addresses change each time (also it's not a good
  // practice to hard-code things in anyway). So I'm wondering
  // if there's a proper/feasible way to do this.

  return 0;
}
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