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我需要一种方法来为函数分配随机值，调用函数并将值打印到屏幕上。

当我按原样运行代码时，不会重新计算敌人的攻击和用户的防御。每次调用函数时，我该怎么做才能让 Python 重新计算这些变量？

import random

enemyName = "Crimson Dragon"

def dragonAtk():
    return random.randint(5,10)

def userDef():
    return random.randrange(8)

userHp = 100
userName = input("What is your name? ")
enemyAttackname = "Fire Blast"

def enemyAttacks():
    global battleDmg
    global userHp
    global enemyAtk
    global userDef

    enemyAtk = dragonAtk()
    userDef = userDef()

    print (">>> " + enemyName + " attacks " + userName + " with "  + enemyAttackname + "!")
    if enemyAtk < userDef:
        print (">>> " + userName + " successfully defended the enemy's attack!")
    elif enemyAtk == userDef:
        print (">>> " + userName + " successfully parried the enemy's attack!")
    else:
        battleDmg = enemyAtk - userDef
        userHp -= battleDmg
        print (">>> " + userName + " takes " + str(battleDmg) + " DMG! "\
        + userName + " has " + str(userHp) + " HP remaining!")

enemyAttacks()
input()
enemyAttacks()
input()

这是我的结果

What is your name? Murk
>>> Crimson Dragon attacks Murk with Fire Blast!
>>> Murk takes 6 DMG! Murk has 94 HP remaining!

Traceback (most recent call last):
  File "C:\Users\Junior\Desktop\python projects\test", line 37, in <module>
    enemyAttacks()
  File "C:\Users\Junior\Desktop\python projects\test", line 22, in enemyAttacks
    userDef = userDef()
TypeError: 'int' object is not callable
>>>

所以，我看到它跑过一次敌人攻击（），但第二次给了我一个错误。不知道该怎么做。有什么想法吗？

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1 回答 1

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这里：

userDef = userDef()

您已经覆盖了您的功能。因此，当您再次调用该函数时，您正在尝试调用该函数，但您有一个整数（因此出现错误）。

将您的变量重命名为另一个名称，这样您就不会覆盖您的函数。

于 2013-09-16T22:50:01.757 回答