1

我能够从二维数组（列）生成平均值。尽管我无法弄清楚如何对该平均值进行排序。我必须创建一个新数组 ( rankedscore[])。

任何帮助将不胜感激：

int rankedArtist() // ranked artist based on score
{
    const int A1_SIZE = 5,  A2_ROWSIZE =5, A2_COLSIZE =10;
    string Artist[A1_SIZE]={ "Degas", "Holbien", "Monet", "Matisse", "Valesquez" };
    int Scores[A2_ROWSIZE][A2_COLSIZE] = {{5,5,6,8,4,6,8,8,8,10},{8,8,8,8,8,8,8,8,8,8},
    {10,10,10,10,10,10,10,10,10,10},{5,0,0,0,0,0,0,0,0,0},{5,6,8,10,4,0,0,0,0,0}};

    cout << "\n\n\t-------------------------------------------" << endl;
    cout << "\t\tRanking by Artist"<< endl;
    cout << "\t===========================================" << endl;

    int total = 0;
    float faverage;
    double AverageScore[5];
    double average;
    double rankedscore[A2_ROWSIZE];


    for (int x=0; x<5; x++)
    {
        cout << "\n\t" << Artist[x] << "\t\t";

        for (int col = 0; col < A2_COLSIZE; col++)
        {
            total+=Scores[x][col];
        }
        faverage = (float)total / 10.0f;

        average = total = 0;
        AverageScore[x] = faverage;
    }
}
4

2 回答 2

1

尽管我无法弄清楚如何对该平均值进行排序。

我会使用 astd::pair将艺术家映射到乐谱。然后我会用它std::sort来实现排序：

#include <vector>
#include <utility>
#include <string>
#include <algorithm>
#include <iostream>

int main()
{
    std::vector<std::string> artists{ "Degas", "Holbien", "Monet", "Matisse", "Valesquez" };
    std::vector<std::vector<int>> scores{{ 3, 2, 1 }, { 5, 4, 3 }};

    std::vector<std::pair<std::string, int>> chart;

    for (auto name = artists.begin(); name != artists.end(); ++name)
    {
        for (auto score = scores.begin(); score != scores.end(); ++score)
        {
            int total = std::accumulate(score->begin(), score->end(), 0);
            int average = total  / score->size();
            chart.push_back(std::make_pair(*name, average));
        }
    }

    struct
    {
        bool operator()(std::pair<std::string, int> p1, std::pair<std::string, int> p2) const
        {
            return p1.second < p2.second;
        }
    } Predicate;

    std::sort(chart.begin(), chart.end(), Predicate);

    for (auto it = chart.begin(); it != chart.end(); ++it)
    {
         std::cout << it->first << ": " << it->second << std::endl;
    }
}
于 2013-09-16T23:13:22.987 回答
0

您可以使用std::sort对rankscore 数组进行排序。之后，只需创建一个 for 循环并打印其值。

您可以在此处查看如何使用的示例std::sort

编辑：由于 RankedScore 和 Artists 应该相关，您可以使用地图结构。使用平均分数作为键。然后您可以按其键对地图进行排序并按顺序打印键值（艺术家）。

于 2013-09-16T22:58:45.863 回答