sql - 选择加入所有匹配项

Question

桌子 ：

CREATE TABLE product_option
(
  id bigint NOT NULL,
  option_type character varying(255) NOT NULL,
  value character varying(255) NOT NULL,
  product_id bigint,
  CONSTRAINT product_option_pkey PRIMARY KEY (id ),
  CONSTRAINT fk_product FOREIGN KEY (product_id)
      REFERENCES product (id) MATCH SIMPLE
      ON UPDATE NO ACTION ON DELETE CASCADE
)

用户可以搜索具有选项列表的产品。即查找具有这些选项的产品：

BINDING_SIDE : BOTTOM
BINDING_SIDE : TOP
BINDING_TYPE : COIL_BINDING

结果应该只返回至少具有这三个选项的产品。（他们可以有更多选择）

Answer 1

option_type, value如果您可以有重复的组合，这将不起作用：

Select
    Product_id
From
    Product_Options
Where
    (Option_Type = 'BINDING_SIDE' and value = 'BOTTOM') Or
    (Option_Type = 'BINDING_SIDE' and value = 'TOP') Or
    (Option_Type = 'BINDING_TYPE' and value = 'BOTTOM') Or
Group By
    Product_id
Having
    Count(*) >= 3

Answer 2

你可以使用HAVINGand 一个条件SUM()来得到这个：

SELECT product_id
FROM YourTable
GROUP BY product_id
HAVING   SUM(CASE WHEN option_type = 'BINDING_SIDE' AND value = 'BOTTOM' THEN 1 ELSE 0 END) >= 1
     AND SUM(CASE WHEN option_type = 'BINDING_SIDE' AND value = 'TOP' THEN 1 ELSE 0 END) >= 1
     AND SUM(CASE WHEN option_type = 'BINDING_TYPE' AND value = 'COIL_BINDING' THEN 1 ELSE 0 END) >= 1

Answer 3

试试这个代码

 SELECT product_id 
FROM product
group by product_id
having SUM(
    (case when (option_type = 'BINDING_SIDE' and value = 'BOTTOM') then 1 else 0 end)
   + (case when (option_type = 'BINDING_SIDE' and value = 'TOP') then 1 else 0 end)
   + (case when (option_type = 'BINDING_SIDE' and value = 'COIL_BINDING') then 1 else 0        end)
      ) >=3