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我有一个制表符分隔的文本文件,其中包含可怕的“NULL”值。经过一番搜索,我发现如何用“某物”替换空字符串……。但是当我这样做时,我似乎失去了一半的价值观。

<cfset thisRow = replace(thisRow, "#chr(9)##chr(9)#", "#chr(9)#ScoobySnack#chr(9)#", "all")>

例如:一行数据包含 120 个“空选项卡” - 但是当我执行此解决方法时 - 我只返回 60。片段在这里:

    <cffile action="read" file="c:\websites\the website\UsageData\#MyFile.NAME#" variable="myDataFile">

  <cfset rowCount = listLen(myDataFile,chr(13))>


  -Other stuff happens-


  <cfloop from="1" to="#rowCount#" index="i">
  <table cellpadding="2" cellspacing="0" border="1">
  <tr>
  <th>ID</th>
  <th>Date</th>
  <th>Time</th>
  <th>DeviceMac</th>
  <th>DeviceAddress</th>
  <th>DeviceName</th>
  <th>UsageBytes</th>
  </tr>
  <!--- set current row to simple variable --->
  <cfset thisRow = listGetAt(myDataFile,i,chr(13))>

  <cfset Field1 = listGetAt(thisRow,1,chr(9))>
  <cfset Field2 = listGetAt(thisRow,2,chr(9))> 
  <cfset Field3 = listGetAt(thisRow,3,chr(9))>


  <cfset thisRow = replace(thisRow, "#chr(9)##chr(9)#", "#chr(9)#ScoobySnack#chr(9)#", "all")>

  <cfset variables.CheckColumnCount = listLen(thisRow,chr(9))>

  <cfif variables.CheckColumnCount NEQ variables.ColumnCount>
  <cfset variables.AdjustedColumnCount = (variables.CheckColumnCount - 3)>
  <cfelse>
  <cfset variables.AdjustedColumnCount = (variables.ColumnCount - 3)>
  </cfif>

  <!---Row #i# Data as a string (#thisRow#)<br/>--->
  <cfset ColNum = 4>
  <!--- now loop the row --->
  <cfloop from="1" to="#variables.AdjustedColumnCount#" index="r">
  <cfif r EQ 1>
  <cfset variables.MyLoopStartTime = variables.MyStartTime>
  <cfelse>

  </cfif>

  <tr>
  <td>#ColNum#</td>
  <td>#variables.thisDate#</td>
  <td>#TimeFormat(variables.MyLoopStartTime,"hh:mm:ss")#</td>
  <td>#Field1#</td>
  <td>#Field2#</td>
  <td>#Field3#</td>
  <td>#listGetAt(thisRow,ColNum,chr(9))#</td>
  </tr>
  <cfset variables.MyLoopStartTime = DateAdd('n', 1, variables.MyLoopStartTime)>
  <cfset ColNum = ColNum +1>
  </cfloop>
  </table>
  <hr>
  <cfset count = count + 1>
  </cfloop>

想法?

4

1 回答 1

1

(来自评论..)

更好的工具来完成这项工作:专门为解析分隔文件而设计的工具。但是,要回答您的问题,如果您必须自己动手,请不要使用replace(). 使用数组更简单,特别是listToArray()includeEmptyFields=true.

读入文件,并在 CR 上拆分内容以创建行数组:

<!--- split content into an array of rows --->
<cfset rowArray  = listToArray(myDataFile, chr(13), true)>
<cfset rowCount  = arrayLen(rowArray)>

然后遍历数组,并从每一行创建一个单独的列数组:

<cfloop from="1" to="#rowCount#" index="rowIndex">
    <!--- split current row into an array of columns --->
    <cfset thisRow  = rowArray[ rowIndex ]>
    <cfset colArray = listToArray(thisRow , chr(9), true)>

    <!--- get first 3 columns (for illustration) --->   
    <cfset Field1 = colArray[ 1 ]>
    <cfset Field2 = colArray[ 2 ]> 
    <cfset Field3 = colArray[ 3 ])>
    ...

</cfloop>

如果你不需要循环索引来做其他事情,你也可以使用数组循环来代替:

<!--- split content into an array of rows --->
<cfset rowArray  = listToArray(myDataFile, chr(13), true)>
<cfloop array="#rowArray#" index="thisRow">
    <!--- split current row into an array of columns --->
    <cfset columns = listToArray(thisRow, chr(9), true)>

    <!--- get first N columns for illustration ---> 
    <cfset Field1 = columns [ 1 ]>
    <cfset Field2 = columns [ 2 ]> 
    <cfset Field3 = columns [ 3 ])>
    ...
</cfloop>
于 2013-09-17T18:06:48.217 回答