python - python中的线性搜索

Question

def search_linear(x,y):
  n = len( x )
  for i in range(n):

  if theValue[i] == y:
        return True

  return false

def main():
  mainValues =int( input("enter the nos first"))
  mV = mainValues.list()

  trgt =int( input('enter a single number to be found in the list'))
  def search_linear(mainValues, trgt)

这是我写的一个简单的线性搜索程序。运行时，它invalid syntax在第 17 行显示，它指向trgt = .... 我不明白我哪里出错了。

我编写搜索函数并在主函数中分配值。这么简单的程序

Answer 1

You don't need def when you call a function. Just use search_linear(mainValues, trgt).

def is only needed when you specify the definition of a function.

Answer 2

usernames = ['AB','CD','EF','GH','IJ','KL']
passwords = ['12','23','56','78','98','76']

def search (x,y):
    n = len(x)
    for i in range(n):
         if usernames[i] == y:
             print("It is here!")
             return True
         else:
             print ("Incorrect!")

mainValues = input("Enter the username")

search(usernames,mainValues)

Answer 3

#Tried my hand at a code by using simple keywords, no functions etc. Ideal for beginners.
ls=[]
n=input("Enter the number of elements in the list:")
k=n-1
for i in range(0,n,1):
    b=raw_input("Enter the elements:")
    ls.append(b)
print ls
element_to_be_searched=raw_input("Enter the element to be searched:")
for j in range(0,k,1):
    if ls[j]==element_to_be_searched:
        if j+1==1:
            print "Search is successful and requested element is the 1st element"
            break
        elif j+1==2:
            print "Search is successful and requested element is the 2nd element"
            break
        elif j+1==3:
            print "Search is successful and requested element is the 3rd element"
            break
        elif j+1>3:
            print "Search is successful and requested element is the ",j+1,"th element"
            break
else:
    print "Sorry,could not find the item you are looking for!"

希望能帮助到你！！！

Answer 4

def LinearSearch(array, targetNumber):
    for i in range (0,5):
        array[i] == targetNumber:
            print("The number %d does exist in the list." %(targetNumber))
        array[i] != targetNumber:
            print("The number %d does not exist in the list." %(targetNumber))

import random
random_number = []
for l in range (0,5):
    random_number.append(random.randint(1,100))

# Algorithm Sort
for i in range(0, 5):
        for j in range (5-1, -1, -1):
            if random_number[j] < random_number[j-1]:
                new_value = random_number[j-1]
                random_number[j-1] = random_number[j]
                random_number[j] = new_value
            if j == 1:
                break