Given a list of tuples, I'm looking to get the most frequently occurring tuple BUT if there are "joint winners" it should pick between them at random.
tups = [ (1,2), (3,4), (5,6), (1,2), (3,4) ]
The above list should return either (1,2) or (3,4) at random for the above list
Use collections.Counter:
>>> collections.Counter([ (1,2), (3,4), (5,6), (1,2), (3,4) ]).most_common()[0]
((1, 2), 2)
This is O(n log(n)).
您可以先使用 Counter 查找重复次数最多的元组。然后找到所需的元组，最后随机化，得到第一个值。
from collections import Counter
import random
tups = [ (1,2), (3,4), (5,6), (1,2), (3,4) ]
lst = Counter(tups).most_common()
highest_count = max([i[1] for i in lst])
values = [i[0] for i in lst if i[1] == highest_count]
random.shuffle(values)
print values[0]
您可以首先对列表进行排序以获取按频率排序的元组。之后，线性扫描可以让您从列表中获得最频繁的元组。总时间O(nlogn)
>>> tups = [ (1,2), (3,4), (5,6), (1,2), (3,4) ]
>>>
>>> sorted(tups)
[(1, 2), (1, 2), (3, 4), (3, 4), (5, 6)]
这个应该及时完成你的任务o(n)：
>>> from random import shuffle
>>> from collections import Counter
>>>
>>> tups = [(1,2), (3,4), (5,6), (1,2), (3,4)]
>>> c = Counter(tups) # count frequencies
>>> m = max(v for _, v in c.iteritems()) # get max frq
>>> r = [k for k, v in c.iteritems() if v == m] # all items with highest frq
>>> shuffle(r) # if you really need random - shuffle
>>> print r[0]
(3, 4)
计数，collections.Counter然后随机选择最常见的：
import collections
import random
lis = [ (1,2), (3,4), (5,6), (1,2), (3,4) ] # Test data
cmn = collections.Counter(lis).most_common() # Numbering based on occurrence
most = [e for e in cmn if (e[1] == cmn[0][1])] # List of those most common
print(random.choice(most)[0]) # Print one of the most common at random
这是另一个没有导入的示例：
listAlphaLtrs = ['b','a','a','b','a','c','a','a','b','c','c','b','a','a','a']
dictFoundLtrs = {i:listAlphaLtrs.count(i) for i in listAlphaLtrs}
maxcnt = 0
theltr = 0
for ltr in dictFoundLtrs:
ltrfound = ltr
foundcnt = dictFoundLtrs[ltr]
if foundcnt > maxcnt:
maxcnt = foundcnt
theltr = ltrfound
print('most: ' + theltr)
资料来源：