python - Python - 计算列表字符串中的单词数

Question

我试图在字符串列表中找到整个单词的数量，这是列表

mylist = ["Mahon Point retail park", "Finglas","Blackpool Mahon", "mahon point  blanchardstown"] 

预期结果：

4
1
2
3

mylist[0] 中有 4 个单词，mylist[1] 中有 1 个单词，以此类推

for x, word in enumerate(mylist):
    for i, subwords in enumerate(word):
        print i

完全不行……

你们有什么感想？

Answer 1

使用str.split：

>>> mylist = ["Mahon Point retail park", "Finglas","Blackpool Mahon", "mahon point  blanchardstown"] 
>>> for item in mylist:
...     print len(item.split())
...     
4
1
2
3

Answer 2

最简单的方法应该是

num_words = [len(sentence.split()) for sentence in mylist]

Answer 3

您可以使用NLTK：

import nltk
mylist = ["Mahon Point retail park", "Finglas","Blackpool Mahon", "mahon point  blanchardstown"]
print(map(len, map(nltk.word_tokenize, mylist)))

输出：

[4, 1, 2, 3]

Answer 4

for x,word in enumerate(mylist):
    print len(word.split())

Answer 5

这是另一种解决方案：

您可以先清理数据，然后计算结果，如下所示：

mylist = ["Mahon Point retail park", "Finglas","Blackpool Mahon", "mahon point  blanchardstown"] 
for item in mylist:
    for char in "-.,":
        item = item.replace(char, '')
        item_word_list = item.split()
    print(len(item_word_list))

结果：

4
1
2
3

Answer 6

mylist = ["Mahon Point retail park", "Finglas","Blackpool Mahon", "mahon point blanchardstown"]
flage = True
for string1 in mylist:
    n = 0
    for s in range(len(string1)):
        if string1[s] == ' ' and flage == False:
            n+=1
        if string1[s] == ' ':
            flage = True
        else:
            flage = False
    print(n+1)

Answer 7

Counter我们可以使用该函数计算一个单词在列表中出现的次数。

from collection import Counter

string = ["mahesh","hello","nepal","nikesh","mahesh","nikesh"]

count_each_word = Counter(string)
print(count_each_word)

输出：

计数器({mahesh:2},{hello:1},{nepal:1},{nikesh:2})

Answer 8

a="hello world aa aa aa abcd  hello double int float float hello"
words=a.split(" ")
words
dic={}
for word in words:
    if dic.has_key(word):
        dic[word]=dic[word]+1
    else:
        dic[word]=1
dic