9

我已经检查了具有 mime 类型的文件。如果它是 jpg 或 gif，它可以完美地使用 

$src = imagecreatefromjpeg($tmpName);

和

$src = imagecreatefromgif($tmpName);

但如果图像是png $src = imagecreatefrompng($tmpName)；

src变量在png案例中为空，但在jpg和gif中显示为resource id.

有人会告诉我我需要做什么吗？

$finfo = finfo_open(FILEINFO_MIME_TYPE);
    $mime = finfo_file($finfo, $_FILES['photo']['tmp_name']);
    unset($_FILES["photo"]["type"]);
    $_FILES["photo"]["type"] = $mime;

    if ((($_FILES["photo"]["type"] == "image/gif") || ($_FILES["photo"]["type"] == "image/jpeg") || ($_FILES["photo"]["type"] == "image/jpg") || ($_FILES["photo"]["type"] == "image/pjpeg") || ($_FILES["photo"]["type"] == "image/x-png") || ($_FILES["photo"]["type"] == "image/png")) && in_array($extension, $allowedExts)) {

        if ($_FILES["photo"]["error"] > 0) {
            echo "Error uploading file <a href='step-1.php'> Try again. </a>";
            $image_check = 0;
            exit;
        } else {

            $image_check = 1;
            $fileName = $_FILES['photo']['name'];
            $tmpName = $_FILES['photo']['tmp_name'];
            $fileSize = $_FILES['photo']['size'];
            $fileType = $_FILES['photo']['type'];
            list($width1, $height1, $typeb, $attr) = getimagesize($tmpName);

            //$filePath = $uploadDir . $fileName;

            $size = filesize($_FILES['photo']['tmp_name']);

             $ext = $_FILES["photo"]["type"];

            if ($ext == 'image/jpeg' || $ext == 'image/jpg') {
            $src = imagecreatefromjpeg($tmpName);
        } else if ($ext == 'image/gif') {
            $src = imagecreatefromgif($tmpName);
        }
            else if(($ext=='image/png')||($ext=='image/x-png'))
         {
            $src = imagecreatefrompng($tmpName);
           }
       $newwidth1 = 624;


        $newheight1 = ($height1 * $newwidth1) / ($width1);
        $tmp = imagecreatetruecolor($newwidth1, $newheight1);

        imagecopyresampled($tmp, $src, 0, 0, 0, 0, $newwidth1, $newheight1, $width1, $height1);
        $filename = "resources/images/" . $append . $_FILES['photo']['name'];

         if ($ext == 'image/jpeg' || $ext == 'image/jpg') {
            imagejpeg($tmp, $filename, 90);
        } else if ($ext == 'image/gif') {
            imagegif($tmp, $filename, 90);
        }
        else if(($ext=='image/png')||($ext=='image/x-png'))
        {

            imagepng($tmp, $filename, 90);
        }
4

2 回答 2

9

写一个文件

<?php
    phpinfo();
?>

浏览它，你会看到JPG Supportand GIF create Supportare enabledbut PNG Supportis disabled。

启用PNG Support，它将起作用。

在此处输入图像描述

于 2013-09-16T06:28:27.087 回答
7

从改变

imagepng($tmp, $filename, 90);

至

imagepng($tmp, $filename);
于 2015-06-12T04:35:31.033 回答