5

我有五个链接，每个链接到一个页面。

function TohokuImgPopup(url) { 
popupWindow = window.open(
                    url, 'popUpWindow'+randomno, 'height=246,width=228,left=0,top=0,resizable=no,scrollbars=no,toolbar=no,menubar=no,location=no,directories=no,status=no')
            }

这是我正在使用的功能。我对 5 个链接有不同的功能，每个链接都会打开一个新窗口。但我一次只能打开一个弹出窗口。如何打开多个弹出窗口？

4

3 回答 3

6

我找到了答案。

<script type="text/javascript">

$(document).ready(


function a1(url) { 
popupWindow1 = window.open(
                    url, 'popUpWindow1', 'height=250,width=234,left=0,top=0,resizable=no,scrollbars=no,toolbar=no,menubar=no,location=no,directories=no,status=no')
            }

            function a2(url) { 
popupWindow2 = window.open(
                    url, 'popUpWindow2', 'height=250,width=234,left=0,top=0,resizable=no,scrollbars=no,toolbar=no,menubar=no,location=no,directories=no,status=no')
            }

            function a3(url) { 
popupWindow3 = window.open(
                    url, 'popUpWindow3', 'height=308,width=299,left=0,top=0,resizable=no,scrollbars=no,toolbar=no,menubar=no,location=no,directories=no,status=no')
            }
            }
</script>

<a href="JavaScript:a1('images/focus_img1.html');">focus 1</a>
<a href="JavaScript:a2('images/focus_img2.html');">focus 2</a>
<a href="JavaScript:a3('images/focus_img3.html');">focus 3</a>

这些链接将在单独的窗口中打开

于 2013-09-29T23:40:25.020 回答
2

I know it's been a long time since the question was asked, but i'll answer because I found nothing on the web that clearly answer the question. An easy way is to use a link with an click() event. 

$('body').on('click', 'a[data-popup]', function(e) {
  var date = new Date();
  var mSec = date.getTime();
  my_window = window.open($(this).attr('href'), "Popup"+mSec, "top=0,left=0,menubar=no,toolbar=no,location=no, height=600, width=800");
  e.preventDefault();
  my_window.focus();
});

using the date.getTime() (It is impossible to have any return value repeated since it's the amount of seconds since 1970 january 1st...) makes each new popup window with a new name :)

于 2019-11-16T02:29:44.670 回答
-1

以下代码将根据需要打开弹出窗口的数量 

<html> 
<head>
<title></title>
<script type="text/javascript">
 function TohokuImgPopup(url) {
window.open(url,"windowName","windowFeatures")
window.open(url,"DifferentWindowName","windowFeatures")// different name for each popup
// create windows as much as you want to create
}
</script>
</head>

<body>
<form>
<input type="button" value="Open Windows" onclick="TohokuImgPopup()">
</form>
</body>

您需要确保每个窗口名称不同，否则最后一个弹出窗口将覆盖它的前一个弹出窗口。结果你会得到一个弹出窗口

于 2018-07-10T08:55:51.753 回答