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我怎样才能收到表单已成功提交的警报?我已经尝试过查看插件的页面,但仍然空手而归。

这是我到目前为止尝试过的代码,也许我的语法有问题:

<script type="text/javascript">

    $(document).ready(function(){

        $('#f1').ajaxForm({

            success: function(){

                alert("Form successfully submitted");

            }

        });

    });

</script>

上面的代码工作并成功地将所有数据插入到表单中,但由于某种原因,在成功提交表单后出现的警报丢失了。

这是表单在提交时使用的脚本:

<?php
$title=$_REQUEST['articletitle'];
$articlemore=$_REQUEST['editor1'];

include "connection.php";

if (isset($_FILES['image']) && $_FILES['image']['size'] > 0)
{

$type=$_FILES['image']['type'];
// Temporary file name stored on the server
$tmpName = $_FILES['image']['tmp_name'];


// Read the file
$fp = fopen($tmpName, 'r');
$data = fread($fp, filesize($tmpName));
$data = addslashes($data);
fclose($fp);


$query = "INSERT INTO blog(articletitle, articleimage, articlemore) VALUES ('$title', '$data', '$articlemore')";
$results = mysqli_query($link, $query);
if(!$results)
{

    echo "Saving Post Failed";
}
else
{
echo "You have a new Post!";
}
}//end if that checks if there is an image


else
{
echo "No image selected/uploaded";
}

// Close our MySQL Link
mysqli_close($link);

?>
4

2 回答 2

0

这是语法

         // wait for the DOM to be loaded 
             $(document).ready(function() { 
        // bind 'myForm' and provide a simple callback function 
        $('#myForm').ajaxForm(function() { 
            alert("Thank you for your comment!"); 
        }); 
    }); 

我希望这能帮到您

于 2013-09-15T09:09:12.213 回答
-1

改变这个:

    $('#f1').ajaxForm({

    $('#f1').ajaxForm(function(){
于 2013-09-15T08:52:14.843 回答