1

我目前正在使用这个 PHP 脚本写入一个文本文件，然后使用另一个从该文本文件中读取，但是如果我添加多个这些（同时更改 textfile.txt 的名称以写入多个文本文件，它用一个字段中更新的任何内容更新了两个文件。我如何能够允许这两个写入多个文本文件而无需将它们复制并粘贴到单独的页面。

用于编辑/更新的 PHP：

<? 
if($_POST['Submit']){ 
$open = fopen("textfile.txt","w+"); 
$text = $_POST['update']; 
fwrite($open, $text); 
fclose($open); 
echo "File updated.<br />";  
echo "File:<br />"; 
$file = file("textfile.txt"); 
foreach($file as $text) { 
echo $text."<br />"; 
} 
}else{ 
$file = file("textfile.txt"); 
echo "<form action=\"".$PHP_SELF."\" method=\"post\">"; 
echo "<textarea Name=\"update\" cols=\"50\" rows=\"10\">"; 
foreach($file as $text) { 
echo $text; 
}  
echo "</textarea>"; 
echo "<input name=\"Submit\" type=\"submit\" value=\"Update\" />\n 
</form>"; 
} 
?>

我意识到我没有发布我的非工作示例，这里是：

<h2>content1</h2>
<? 
if($_POST['Submit']){ 
$open = fopen("../content.txt","w+"); 
$text = $_POST['update']; 
fwrite($open, $text); 
fclose($open); 
echo "File updated.<br />";  
echo "File:<br />"; 
$file = file("../content.txt"); 
foreach($file as $text) { 
echo $text."<br />"; 
} 
}else{ 
$file = file("../content.txt"); 
echo "<form action=\"".$PHP_SELF."\" method=\"post\">"; 
echo "<textarea Name=\"update\" cols=\"50\" rows=\"10\">"; 
foreach($file as $text) { 
echo $text; 
}  
echo "</textarea>"; 
echo "<input name=\"Submit\" type=\"submit\" value=\"Update\" />\n 
</form>"; 
} 
?> 
<br />
<h2>content2</h2>
<? 
if($_POST['Submit']){ 
$open = fopen("../content2.txt","w+"); 
$text = $_POST['update']; 
fwrite($open, $text); 
fclose($open); 
echo "File updated.<br />";  
echo "File:<br />"; 
$file = file("../content2.txt"); 
foreach($file as $text) { 
echo $text."<br />"; 
} 
}else{ 
$file = file("../content2.txt"); 
echo "<form action=\"".$PHP_SELF."\" method=\"post\">"; 
echo "<textarea Name=\"update\" cols=\"50\" rows=\"10\">"; 
foreach($file as $text) { 
echo $text; 
}  
echo "</textarea>"; 
echo "<input name=\"Submit\" type=\"submit\" value=\"Update\" />\n 
</form>"; 
} 
?>
4

1 回答 1

3

好的，我解决了自己的问题，这是一个愚蠢的问题，我忘记为字段提供唯一名称：

<h2>content1</h2>
<? 
if($_POST['Submit']){ 
$open = fopen("../content.txt","w+"); 
$text = $_POST['update']; 
fwrite($open, $text); 
fclose($open); 
echo "File updated.<br />";  
echo "File:<br />"; 
$file = file("../content.txt"); 
foreach($file as $text) { 
echo $text."<br />"; 
} 
}else{ 
$file = file("../content.txt"); 
echo "<form action=\"".$PHP_SELF."\" method=\"post\">"; 
echo "<textarea Name=\"update\" cols=\"50\" rows=\"10\">"; 
foreach($file as $text) { 
echo $text; 
}  
echo "</textarea>"; 
echo "<input name=\"Submit\" type=\"submit\" value=\"Update\" />\n 
</form>"; 
} 
?> 
<br />
<h2>content2</h2>
<? 
if($_POST['Submit2']){ 
$open = fopen("../content2.txt","w+"); 
$text = $_POST['update2']; 
fwrite($open, $text); 
fclose($open); 
echo "File updated.<br />";  
echo "File:<br />"; 
$file = file("../content2.txt"); 
foreach($file as $text) { 
echo $text."<br />"; 
} 
}else{ 
$file = file("../content2.txt"); 
echo "<form action=\"".$PHP_SELF."\" method=\"post\">"; 
echo "<textarea Name=\"update2\" cols=\"50\" rows=\"10\">"; 
foreach($file as $text) { 
echo $text; 
}  
echo "</textarea>"; 
echo "<input name=\"Submit2\" type=\"submit\" value=\"Update\" />\n 
</form>"; 
} 
?>
于 2013-09-15T00:06:46.003 回答