我正在尝试开始学习使用 Perlin Noise 来创建瓦片图。我才刚刚开始,所以我在网上找到了一些源代码来创建基于 Perlin Noise 的数组。所以我现在有一个很好的数据数组(据我所知),但我不明白可以使用哪种方法将其从数组转换为瓦片地图。
有没有人有任何方法的例子或来源可以做到这一点?
这是我使用生成数组的代码。
package perlin1;
import java.util.Random;
public class ImageWriter {
/** Source of entropy */
private Random rand_;
/** Amount of roughness */
float roughness_;
/** Plasma fractal grid */
private float[][] grid_;
/** Generate a noise source based upon the midpoint displacement fractal.
*
* @param rand The random number generator
* @param roughness a roughness parameter
* @param width the width of the grid
* @param height the height of the grid
*/
public ImageWriter(Random rand, float roughness, int width, int height) {
roughness_ = roughness / width;
grid_ = new float[width][height];
rand_ = (rand == null) ? new Random() : rand;
}
public void initialise() {
int xh = grid_.length - 1;
int yh = grid_[0].length - 1;
// set the corner points
grid_[0][0] = rand_.nextFloat() - 0.5f;
grid_[0][yh] = rand_.nextFloat() - 0.5f;
grid_[xh][0] = rand_.nextFloat() - 0.5f;
grid_[xh][yh] = rand_.nextFloat() - 0.5f;
// generate the fractal
generate(0, 0, xh, yh);
}
// Add a suitable amount of random displacement to a point
private float roughen(float v, int l, int h) {
return v + roughness_ * (float) (rand_.nextGaussian() * (h - l));
}
// generate the fractal
private void generate(int xl, int yl, int xh, int yh) {
int xm = (xl + xh) / 2;
int ym = (yl + yh) / 2;
if ((xl == xm) && (yl == ym)) return;
grid_[xm][yl] = 0.5f * (grid_[xl][yl] + grid_[xh][yl]);
grid_[xm][yh] = 0.5f * (grid_[xl][yh] + grid_[xh][yh]);
grid_[xl][ym] = 0.5f * (grid_[xl][yl] + grid_[xl][yh]);
grid_[xh][ym] = 0.5f * (grid_[xh][yl] + grid_[xh][yh]);
float v = roughen(0.5f * (grid_[xm][yl] + grid_[xm][yh]), xl + yl, yh
+ xh);
grid_[xm][ym] = v;
grid_[xm][yl] = roughen(grid_[xm][yl], xl, xh);
grid_[xm][yh] = roughen(grid_[xm][yh], xl, xh);
grid_[xl][ym] = roughen(grid_[xl][ym], yl, yh);
grid_[xh][ym] = roughen(grid_[xh][ym], yl, yh);
generate(xl, yl, xm, ym);
generate(xm, yl, xh, ym);
generate(xl, ym, xm, yh);
generate(xm, ym, xh, yh);
}
/**
* Dump out as a CSV
*/
public void printAsCSV() {
for(int i = 0;i < grid_.length;i++) {
for(int j = 0;j < grid_[0].length;j++) {
System.out.print(grid_[i][j]);
System.out.print(",");
}
System.out.println();
}
}
/**
* Convert to a Boolean array
* @return the boolean array
*/
public boolean[][] toBooleans() {
int w = grid_.length;
int h = grid_[0].length;
boolean[][] ret = new boolean[w][h];
for(int i = 0;i < w;i++) {
for(int j = 0;j < h;j++) {
ret[i][j] = grid_[i][j] < 0;
}
}
return ret;
}
/** For testing */
public static void main(String[] args) {
ImageWriter n = new ImageWriter(null, 1.0f, 250, 250);
n.initialise();
n.printAsCSV();
}
}
结果数组是 0 到 1 之间的所有数量。
同样,我只是在寻找如何将这个数组转换为瓦片地图。任何帮助表示赞赏。谢谢