所以我有以下数组结构:
{
"_": {
"APP_ID": "server_tracked"
},
"success": true,
"requestTime": "2013-09-14T15:05:28-07:00",
"shard": "North_America:OTg0ZGYzNjA0OGYxNjAyNWUzZjVlNTQwZDk4YTdjNTYzMGE3NTA4Ng",
"player": {
"accountId": xxx,
"summonerId": xx,
"name": "xx",
"icon": xx,
"internalName": "xx",
"level": xx
},
"data": {
"lifetimeStatistics": {
"array": [
{
"count": 1,
"statType": "TOTAL_SESSIONS_PLAYED",
"dataVersion": 0,
"value": 1,
"championId": 111,
"futureData": null
},
{
"count": 0,
"statType": "TOTAL_SESSIONS_LOST",
"dataVersion": 0,
"value": 0,
"championId": 111,
"futureData": null
},
[...]
我想搜索一个“子数组”,其中值“championId”= x 和 statType = y。如果该数组,我将拥有 [x],然后我应该能够返回该数组中的任何值。
这是我目前拥有的一些 PHP 代码:
$result = json_decode($response -> raw_body);
$array = $result->data->lifetimeStatistics->array;
$search1 = x;
$search2 = y;
$cluster=false;
foreach ($array as $n=>$c) {
if (in_array($search, $c)) {
$cluster=$n; break;
}
}
作为附加信息,我将使用$response = Unirest::get
它来获取数组。
编辑完整代码:
$result = json_decode($response -> raw_body);
$haystack = $result->data->lifetimeStatistics->array;
$searchx = x;
$searchy = y;
$arrayNumber = null;
foreach ($haystack as $n=>$c) {
if ($c->championId === $searchx && $c->statType === $searchy) {
$arrayNumber = $n;
}
}
// We now get the value from that array
$array = $result->data->lifetimeStatistics->array[$arrayNumber]->value;
return $array;