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我有一个 sapi 语法

<rule id="root">
    <item repeat="0-">
       <ruleref uri="#digit"></ruleref>
     </item>
 </rule>

<rule id="digit">
<one-of>
      <item>1</item>
      <item>2</item>
      <item>3</item>
      <item>4</item>
      <item>5</item>
      <item>6</item>
      <item>7</item>
      <item>8</item>
      <item>9</item>
      <item>0</item>
  </one-of>
 </rule>

我想要相当于动态加载语法，有人可以帮我吗？

我努力了

SPSTATEHANDLE hRule;
hr = cpGrammar->GetRule(L"digit", NULL, SPRAF_TopLevel | SPRAF_Active, TRUE,&hRule);
hr = cpGrammar->AddWordTransition(hRule, NULL, L"1", NULL, SPWT_LEXICAL, 1, NULL);
hr = cpGrammar->AddWordTransition(hRule, NULL, L"2", NULL, SPWT_LEXICAL, 1, NULL);
hr = cpGrammar->AddWordTransition(hRule, NULL, L"3", NULL, SPWT_LEXICAL, 1, NULL);
hr = cpGrammar->AddWordTransition(hRule, NULL, L"4", NULL, SPWT_LEXICAL, 1, NULL);
hr = cpGrammar->AddWordTransition(hRule, NULL, L"5", NULL, SPWT_LEXICAL, 1, NULL);
hr = cpGrammar->AddWordTransition(hRule, NULL, L"6", NULL, SPWT_LEXICAL, 1, NULL);
hr = cpGrammar->AddWordTransition(hRule, NULL, L"7", NULL, SPWT_LEXICAL, 1, NULL);
hr = cpGrammar->AddWordTransition(hRule, NULL, L"8", NULL, SPWT_LEXICAL, 1, NULL);
hr = cpGrammar->AddWordTransition(hRule, NULL, L"9", NULL, SPWT_LEXICAL, 1, NULL);
hr = cpGrammar->AddWordTransition(hRule, NULL, L"0", NULL, SPWT_LEXICAL, 1, NULL);
hr = cpGrammar->Commit(NULL);
hr = cpGrammar->SetGrammarState(SPGS_ENABLED);

它对我不起作用，我做对了吗？

4

1 回答 1

0

查看了一些构建动态语法的代码，我很确定您需要SPRAF_Dynamic与SPRAF_TopLevel | SPRAF_Active. （至少，我写的代码使用了它。）

于 2013-09-19T05:58:04.177 回答