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当我在 mysql 中测试这个查询时它很好，但是当我在 php 中运行它时，我不断收到这个错误。

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'SELECT *, (@rownum := @rownum + 1) AS rank FROM ( SELECT *, (totalWins+(total' at line 1

这是我拥有的 php 代码。

    <?php

    $sql = "    SET @rownum = 0; ";

    $sql .= "   SELECT *,  (@rownum := @rownum + 1) AS rank FROM ( ";

    $sql .= "       SELECT *, (totalWins+(totalPushs*.5)) AS totalPoints, totalWins+totalLost+totalPushs AS totalBets FROM ( ";

    $sql .= "           SELECT *, SUM(win) AS totalWins, SUM(lost) AS totalLost, SUM(push) AS totalPushs FROM ( ";

    $sql .= "               SELECT *, (finalResult = 'Winner') AS win, (finalResult = 'Loser') AS lost, (finalResult = 'Push') AS push FROM ( ";

    $sql .= "                   SELECT " . $db_prefix . "users.userID, userName, ";
    $sql .= "                   IF (pickID=visitorID, visitorResult, homeResult) AS finalResult ";
    $sql .= "                   FROM " . $db_prefix . "users ";
    $sql .= "                   JOIN " . $db_prefix . "picks ";
    $sql .= "                   ON " . $db_prefix . "users.userID = " . $db_prefix . "picks.userID ";
    $sql .= "                   JOIN " . $db_prefix . "schedule ";
    $sql .= "                   ON " . $db_prefix . "picks.gameID = " . $db_prefix . "schedule.gameID ";

    $sql .= "               ) x ";

    $sql .= "           ) x ";
    $sql .= "           GROUP BY userID ";

    $sql .= "       ) x ";

    $sql .= "   ) x ";
    $sql .= "   ORDER BY totalPoints DESC, totalWins DESC, totalPushs DESC, totalLost ";

    $result = mysql_query($sql) or die(mysql_error());

    while ($row = mysql_fetch_array($result)) {

        echo $row[rank] . '|' . $row[userName]. '|' . $row[totalWins] . '|' . $row[totalLost] . '|' . $row[totalPushs] . '|' . $row[totalPoints];
        echo '<br>';

    }

    ?>

我可以让 php 代码在没有第一行代码的情况下工作

$sql = " SET @rownum = 0; ";

但它不会回显排名列。

当它在 php 中时，我必须做一些不同的事情来行其中一个代码吗？

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2 回答 2

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mysql_query不支持一次运行多个查询。您必须先运行
mysql_query("SET @rownum = 0;");，然后mysql_query才能在第二次调用中运行其余的查询。

于 2013-09-14T14:02:02.717 回答
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请尝试使用 tablename.* 而不是 *

于 2013-09-14T14:02:55.963 回答