1

我有 3 个表代表这样的容器-容器关系：

create table Containee(id int, name varchar(100), primary key(id));
create table Container(id int, name varchar(100), sourceId int, sourceType varchar(100), primary key(id));
create table JoinTable(containeeId int, resourceId int, resourceType varchar(100), primary key(containeeId, resourceId, resourceType));

休眠实体映射如下

@Entity
public class Containee {

@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private int id;

@Basic
private String name;
}

@Entity
public class Container implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private int id;

@Basic
private String name;

@Embedded
@AttributeOverrides({
    @AttributeOverride(name = "id", column = @Column(name = "sourceId")),
    @AttributeOverride(name = "type", column = @Column(name = "sourceType"))
})
private DomainObject domainObject;

@OneToMany(fetch = FetchType.LAZY)
@JoinTable(name = "JoinTable", 
    joinColumns = {
        @JoinColumn(name="resourceId", referencedColumnName = "sourceId"),
        @JoinColumn(name="resourceType", referencedColumnName = "sourceType")
    }, 
    inverseJoinColumns = @JoinColumn(name = "containeeId")
)
private Collection<Containee> containees;
}

嵌入的类被声明为

@Embeddable
public class DomainObject {
private int id;
private String type;

public int getId() {
    return id;
}

public String getType() {
    return type;
}

}

上面的代码不起作用，我收到以下错误：

引用 Container 的容器的 referencedColumnNames(sourceId, sourceType) 未映射到单个属性。

但是，如果我删除 @Embedded domainObject 字段并将其替换为 2 个 @Basic sourceId 和 sourceType，则相同的代码就像一个魅力。我已经尝试了很多东西，但似乎也没有任何东西适用于 @Embedded 字段。任何帮助表示赞赏！

4

1 回答 1

0

为 sourceId 和 sourceType 添加另外 2 个 @Basic 字段解决了这个问题！

于 2013-09-20T10:43:57.940 回答