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我是 Rails 的新手，我正在创建一个用户可以登录的应用程序，它会动态生成一个表，他们可以在其中进行输入。我已经成功登录，但我不知道如何创建一个与用户关联的表。

我的 users_controller.rb 类：

class UsersController < ApplicationController
  before_action :set_user, only: [:show, :edit, :update, :destroy]

  # GET /users
  # GET /users.json
  def index
    @users = User.order(:name)
  end

  # GET /users/1
  # GET /users/1.json
  def show
  end

  # GET /users/new
  def new
    @user = User.new 
  end

  # GET /users/1/edit
  def edit
  end

  # POST /users
  # POST /users.json
  def create
    @user = User.new(user_params)

    respond_to do |format|
      if @user.save
        format.html { redirect_to login_url, notice: "User #{@user.name} was successfully created." }
        format.json { render action: 'show', status: :created, location: @user }

#HERE I WOULD LIKE TO CREATE A TABLE ASSOSSIATED TO THE USER
        @rapport_table = User.rapport_table.create

      else
        format.html { render action: 'new' }
        format.json { render json: @user.errors, status: :unprocessable_entity }
      end
    end
  end

  # PATCH/PUT /users/1
  # PATCH/PUT /users/1.json
  def update
    respond_to do |format|
      if @user.update(user_params)
        format.html { redirect_to users_url, notice: "User #{@user.name} was successfully updated." }
        format.json { head :no_content }
      else
        format.html { render action: 'edit' }
        format.json { render json: @user.errors, status: :unprocessable_entity }
      end
    end
  end

  # DELETE /users/1
  # DELETE /users/1.json
  def destroy
    @user.destroy
    respond_to do |format|
      format.html { redirect_to users_url }
      format.json { head :no_content }
    end
  end

  private
    # Use callbacks to share common setup or constraints between actions.
    def set_user
      @user = User.find(params[:id])
    end

    # Never trust parameters from the scary internet, only allow the white list through.
    def user_params
      params.require(:user).permit(:name, :password, :password_confirmation)
    end
end

rapport_table.rb

class RapportTable < ActiveRecord::Base
    belongs_to :user
end

12341324123_create_rapport_tables.rb

class CreateRapportTables < ActiveRecord::Migration
  def self.up
    create_table :rapport_tables do |t|
      t.date :date
      t.text :description
      t.integer :time

      t.timestamps
    end
  end
  def self.down
    drop_table :rapport_tables
  end
end

显示.html.erb

<p id="notice"><%= notice %></p>

<p>
  <strong>Name:</strong>
  <%= @user.name %>
</p>



<%= link_to 'Edit', edit_user_path(@user) %> |
<%= link_to 'Back', users_path %>
4

1 回答 1

1

您永远不会想要在运行时的数据库中创建表。相反，您需要创建更多模型：

class RaportTable < ActiveRecord::Base
  belongs_to :user
  has_many :columns
  has_many :rows
end

class Column < ActiveRecord::Base
  # attr_accessible :name, :order
  belongs_to :raport_table
  has_many :cells
end

class Row < ActiveRecord::Base
  # attr_accessible :row_number
  belongs_to :raport_table
  has_many :cells
end

class Cell < ActiveRecord::Base
  # attr_accessible :value
  belongs_to :column
  belongs_to :row
end

这应该足够开始了。

于 2013-09-13T23:09:34.267 回答