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我曾尝试使用此代码计算 12 个月移动平均线。我在第三列下面的数据是我想计算平均值的值。
此代码的问题在于它输出移动平均值作为转换为双倍的值

//a is an object of the larger class
//x is the collection of values to be averaged
public int bars = 1;
double[] movavg = new double[x.length - bars]; // 
int k = 0;
try {
    for (int i = a.bars - 1; i < a.x.length - 1; i++) // for each bar
    {
        a.movavg[a.k] = 0.0;
        for (int j = 0; j < a.bars; j++) // sum over  'bars' previous input values
        {
            a.movavg[a.k] += a.x[i - j];
        }
        double k = a.movavg[a.k++] /= a.bars; // divide by number of bars

        System.out.println(i + "   " + k + "    " + a.avgNumerator[i]);
    }
} catch (ArrayIndexOutOfBoundsException e) {
    e.printStackTrace();
}
}

year month  value_for_moving_average
2011   1    21333333
2011   2    13500000
2011   3    17285714
2011   4    15500000
2011   5    15800000
2011   6    15900000
2011   7    15875000
2011   8    15600000
2011   9    17666666
2011   10   20000000
2011   11   15958333
2011   12   21583333
2012   1    21519230
2012   2    25450000
2012   3    21400000
2012   4    34166666
2012   5    27928571
2012   6    29250000
2012   7    17550000
2012   8    19111111
2012   9    18200000
2012   10   15181818
2012   11   14455555
2012   12   16900000
2013   1    13500000
2013   2    13600000
2013   3    12812500

结果应该是这样

moving_average
15,868,750
16,446,875
17,228,571
17,098,113
17,056,140
17,512,727
15,891,379
16,056,923
16,188,571
16,515,385
16,270,833
16,671,053
17,241,279
18,296,196
18,547,222
19,431,548
20,334,302
21,014,706
21,089,080
21,520,349
21,408,333
20,737,500
20,745,876
20,493,229
19,597,849
18,323,656
17,704,167

但我刚开始的输出是这样的

2.1333333E7
1.35E7
1.7285714E7
1.55E7
1.58E7
1.59E7
1.5875E7
1.56E7
1.7666666E7
2.0E7
1.5958333E7
2.1583333E7
2.151923E7
2.545E7
2.14E7
3.4166666E7
2.7928571E7
2.925E7
1.755E7
1.9111111E7
1.82E7
1.5181818E7
1.4455555E7
1.69E7
1.35E7
1.36E7

就像代码输出相同的值但转换为双精度

4

1 回答 1

0

此代码的问题在于它输出移动平均值作为转换为双倍的值

这是意料之中的，因为您将平均值计算为双倍。如果您只是想将双重平均值转换为整数，请使用Math.round(double); 例如

    System.out.println(i + "   " + k + "    " + 
                       Math.round(a.avgNumerator[i]));
于 2013-09-13T13:53:18.887 回答