2

I'm beginner JAVA programming. I'm making model class through XML parsing. I know there are some example such as : JAXB, xmapper etc.. I have some xml file which element has iteration. How to create model class for this xml ? Any help.. Let’s map some xml: 

<root a="2.2">
    <main>
      <node1>123</node1>
      <node2>123</node2>
    </main>

    <client value="1" use="true">
      <C_node1>aaa</C_node1>
      <C_node2>bbb</C_node2>
    </client>

    <client value="2" use="true">
      <C_node1>aaa</C_node1>
      <C_node2>bbb</C_node2>
    </client>

    <client value="3" use="true">
      <C_node1>aaa</C_node1>
      <C_node2>bbb</C_node2>
    </client>


    // ...
    <client value="100" use="true">
      <C_node1>aaa</C_node1>
      <C_node2>bbb</C_node2>
    </client>    

    <System>     
     <DebugFrame>0</DebugFrame>     
    </System>

</root>

I found http://docs.oracle.com/cd/E12840_01/wls/docs103/webserv/data_types.html. Is that what I want ?

Edited Here is real code. I have some compile error. Java version is 

java version "1.7.0_25"
Java(TM) SE Runtime Environment (build 1.7.0_25-b17)
Java HotSpot(TM) 64-Bit Server VM (build 23.25-b01, mixed mode)

Here is error message ;

com.sun.xml.internal.bind.v2.runtime.IllegalAnnotationsException: 2 counts of IllegalAnnotationExceptions
Class has two properties of the same name "mode"
    this problem is related to the following location:
        at public java.lang.String xmlParserTest.RootTest.getMode()
        at xmlParserTest.RootTest
    this problem is related to the following location:
        at private java.lang.String xmlParserTest.RootTest.mode
        at xmlParserTest.RootTest
Class has two properties of the same name "inputFile"
    this problem is related to the following location:
        at public java.lang.String xmlParserTest.MainEntity.getInputFile()
        at xmlParserTest.MainEntity
        at private xmlParserTest.MainEntity xmlParserTest.RootTest.main
        at xmlParserTest.RootTest
    this problem is related to the following location:
        at private java.lang.String xmlParserTest.MainEntity.inputFile
        at xmlParserTest.MainEntity
        at private xmlParserTest.MainEntity xmlParserTest.RootTest.main
        at xmlParserTest.RootTest

: console.java 

package xmlParserTest;

import java.io.File;

import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBException;
import javax.xml.bind.Unmarshaller;

public class console {

    public static void main(String[] args) {

       try
       {                    
          JAXBContext jc = JAXBContext.newInstance(RootTest.class);
            Unmarshaller u = jc.createUnmarshaller();

            File f = new File("Testing.xml");
            RootTest product = (RootTest) u.unmarshal(f);

            System.out.println(product.getMode());
            System.out.println(product.getMainEntity().getInputFile());
            System.out.println(product.getMainEntity().getOutputFolder());


    }catch (JAXBException e) {
       e.printStackTrace();
      } 
    }

}

: RootTest.java 

package xmlParserTest;

import javax.xml.bind.annotation.XmlAttribute;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;

@XmlRootElement(name = "Function")
public class RootTest {

    private MainEntity main;
    private String mode;            

    @XmlElement(name="Main")
    public MainEntity getMainEntity() {
     return main;
    }

    public void setMainEntity(MainEntity _main) {
     this.main = _main;
    }

    @XmlAttribute(name="mode")
    public String getMode() {
     return mode;
    }

    public void setMode(String _mode) {
      this.mode = _mode;
    }       

    public RootTest()
    {   
    }
}

: MainEntity.java 

package xmlParserTest;

import javax.xml.bind.annotation.XmlElement;

public class MainEntity {

    private String inputFile;   
    private String inputType;   
    private String outputFolder;    
    private String outputType;  

    @XmlElement(name="InputFile")
    public String getInputFile() {
      return inputFile;
    }

    public void setInputFile(String _inputFile) {
      this.inputFile = _inputFile;
    }       

    public String getInputType() {
      return inputType;
    }

    public void setInputType(String _type) {
      this.inputType = _type;
    }

    @XmlElement(name="OutputFolder")
    public String getOutputFolder() {
      return outputFolder;
    }

    public void setOutputFolder(String _outputFolder) {
      this.outputFolder = _outputFolder;
    }   

    public String getOutputType() {
      return outputType;
    }

    public void setOutputType(String _type) {
      this.outputType = _type;
    }

    public MainEntity()
    {
    }   
}

: Testing.xml

<?xml version="1.0" encoding="UTF-8"?>
<Function mode="Execute">
  <Main>
    <InputFile type="string">C:\DATA\test.txt</InputFile>
    <OutputFolder type="string">C:\Test</OutputFolder>
  </Main>
</Function>
4

2 回答 2

3

如果您想使用 JAXB，首先，您需要创建主模型，如下所示：

@XmlRootElement(name = "root")
@XmlAccessorType(XmlAccessType.FIELD)
public class Root {
    private MainEntity main;
    @XmlElement(name = "client")
    private List<ClientEntity> clients;
    @XmlAttribute
    private String a;
    @XmlElement(name = "System")
    private SystemEntity system;
//getters and setters for all fields
}

然后，指定实体：

public class MainEntity {
    private String node1;
    private String node2;
//getters and setters for all fields
}

@XmlAccessorType(XmlAccessType.FIELD)
public class ClientEntity {
    @XmlElement(name = "C_node1")
    private String C_node1;
    @XmlElement(name = "C_node2")
    private String C_node2;
    @XmlAttribute
    private Long value;
    @XmlAttribute
    private boolean use;
//getters and setters for all fields
}

@XmlAccessorType(XmlAccessType.FIELD)
public class SystemEntity {
    @XmlElement(name = "DebugFrame")
    private Long debugFrame;
//getters and setters for all fields
}

如您所见，我们使用 @XmlElement(name = "System") 为字段设置别名，并使用 @XmlAttribute 从属性中读取字段。

要使用 JAXB 解组 XML，请为您的类模型创建上下文：

JAXBContext context = JAXBContext.newInstance(Root.class);
Unmarshaller unmarshaller = context.createUnmarshaller();
Root root = (Root) unmarshaller.unmarshal(file);

不要忘记：当您创建模型时，您需要为要编组/解组的字段指定 getter 和 setter，并为类指定非参数构造函数。

有关注释的更多信息您可以在此处找到： http ://www.techferry.com/articles/jaxb-annotations.html

玩得开心！：）

于 2013-09-13T10:52:29.823 回答
1

使用 JAXB，您可以创建所需的 Java 类，如下所示：

@XmlRootElement(name = "main")
public class Main {
String node1;
String node1;
//getters and setters for fields
}

@XmlRootElement(name = "client")
public class Client {
String node1;
String node1;

@XmlAttribute
private boolean use;
@XmlAttribute
private int value;
//getters and setters for fields
}

然后创建一个Root类来表示您的 XML 文件：

@XmlRootElement(name = "root")
public class Root {
//add a list of client instances
@XmlElement(name = "client")
private List<Client> clientList;
//add an instance of main
@XmlElement(name = "main")
private Main main;
// setters to set the values for main and clients
}

现在，使用这些代码行，您可以为Root该类创建 XML 表示：

Root root = new Root();

root.setMain(CREATE_AND_SET_AN_INSTANCE_OF_MAIN);
root.setClientList(CREATE_AND_SET_A_LIST_OF_CLIENTS);

String filePath = "PATH_TO_SAVE_YOUR_FILE";
File file = new File(filePath);
JAXBContext jaxbContext = JAXBContext.newInstance(Root.class);
Marshaller jaxbMarshaller = jaxbContext.createMarshaller();


jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);

jaxbMarshaller.marshal(alpha, file);

您可以使用这些代码行将 XML 读回 Java 对象：

String filePath = "XML_FILE_PATH";
File file = new File(filePath);
JAXBContext jaxbContext = JAXBContext.newInstance(Root.class);

Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
Root root = (Root) jaxbUnmarshaller.unmarshal(file);

参考：用于 XML 绑定的 Java 架构 (JAXB)

于 2013-09-13T11:03:09.610 回答