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我正在尝试从基节点到其根节点的路径为 1 行。Cypher 查询如下所示：

start n = node:node_auto_index(Name = "user1") match path = (n-[r:IS_MEMBER_OF_GROUP*]->b) return last(collect(distinct path));

但是当将其更改为 Neo4JClient 语法时：

var k = clientConnection.Cypher
                .Start(new { n = "node:node_auto_index(Name = 'user1')" })
                .Match("path = (n-[r:IS_MEMBER_OF_GROUP*]->b)")
                .ReturnDistinct<Node<Principles>>("last(collect(path))").Results;

它得到一个错误：

{"Value cannot be null.\r\nParameter name: uriString"}

从那里继续时：

 Neo4jClient encountered an exception while deserializing the response from the server. This is likely a bug in Neo4jClient.



Please open an issue at https://bitbucket.org/Readify/neo4jclient/issues/new



To get a reply, and track your issue, ensure you are logged in on BitBucket before submitting.



Include the full text of this exception, including this message, the stack trace, and all of the inner exception details.



Include the full type definition of Neo4jClient.Node`1[[IQS_Neo4j_TestGraph.Nodes.Principles, IQS Neo4j TestGraph, Version=1.0.0.0, Culture=neutral, PublicKeyToken=null]].



Include this raw JSON, with any sensitive values replaced with non-sensitive equivalents:



{

  "columns" : [ "last(collect(path))" ],

  "data" : [ [ {

    "start" : "http://localhost:7474/db/data/node/3907",

    "nodes" : [ "http://localhost:7474/db/data/node/3907", "http://localhost:7474/db/data/node/3906", "http://localhost:7474/db/data/node/3905", "http://localhost:7474/db/data/node/3904" ],

    "length" : 3,

    "relationships" : [ "http://localhost:7474/db/data/relationship/4761", "http://localhost:7474/db/data/relationship/4762", "http://localhost:7474/db/data/relationship/4763" ],

    "end" : "http://localhost:7474/db/data/node/3904"

  } ] ]

}

如何将密码查询转换为 Neo4JClient 查询？

4

1 回答 1

3

好吧，您返回的东西是 a PathsResultnot a Node<>，所以如果您将查询更改为：

 var k = clientConnection.Cypher
            .Start(new { n = "node:node_auto_index(Name = 'user1')" })
            .Match("path = (n-[r:IS_MEMBER_OF_GROUP*]->b)")
            .ReturnDistinct<PathsResult>("last(collect(path))").Results; //<-- Change here

你会得到结果，如果你特别想要这篇文章的节点，这将返回我从对我的数据库运行查询中得到的结果：Getting PathsResults涵盖了转换为实际节点和关系。

另一件事（这将有助于查询更好地执行，因为 neo4j 可以更轻松地缓存执行计划），您可以start通过执行以下操作更改您的参数以使其使用参数：

.Start(new { n = Node.ByIndexLookup("node_auto_index", "Name", "user1")})
于 2013-09-13T07:37:32.253 回答