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我正在做这个任务,我们需要创建一个小的网络应用程序,让某人在三明治上点他们想要的东西,然后用更简单的术语来表示任何人得到了制作三明治的订单。

我已经问了几个关于这个的问题,但是我遇到了最后一个障碍,已经解决了一个小时,并且无法弄清楚出了什么问题。如果我只是注释掉 PHP 中的 cheesetype 开关,一切都会正常工作,但是一旦我重新引入它,就会出现服务器错误。我检查了所有语法三倍以上,但是一旦该开关出现,事情就会变得不稳定。我做错了什么?

HTML

<!DOCTYPE html>
<html>
<head>
<title>Sandwich Order</title>
</head>
<body>
<form name="sandwichform" method="post" action="sandwichmaker.php">
Size
<select name="size">
    <option value="small">Small</option>
    <option value="medium">Medium</option>
    <option value="large">Large</option>
</select><br/>
Meat Type
<select name="meattype">
    <option value="ham">Ham</option>
    <option value="turkey">Turkey</option>
    <option value="beef">Roast Beef</option>
    <option value="salami">Salami</option>
</select><br/>
Cheese
<select name="cheesetype">
    <option value="american">American</option>
    <option value="swiss">Swiss</option>
    <option value="jack">Monterey Jack</option>
</select><br/>
Bread Type
<select name="breadtype">
    <option value="white">White</option>
    <option value="wheat">Wheat</option>
</select><br/>
Condiments<br/>
Ketchup<input type="checkbox" name="condiments[]" value="ketchup"><br>
Mustard<input type="checkbox" name="condiments[]" value="mustard"><br>
Mayonnaise<input type="checkbox" name="condiments[]" value="mayo"><br>
BBQ Sauce<input type="checkbox" name="condiments[]" value="bbq"><br>
<b>Extras:</b><br/>
Tomato<input type="checkbox" name="extras[]" value="tomato"><br>
Lettuce<input type="checkbox" name="extras[]" value="lettuce"><br>
<input type="submit" name="submit" value="Submit"/>
</form>
</body>
</html>

PHP

<?php

$breadtype=$_POST['breadtype'];
$size=$_POST['size'];
$meattype=$_POST['meattype'];
$cheesetype=$_POST['cheesetype'];
$condiments=$_POST['condiments'];
$extras=$_POST['extras'];

if ($breadtype == "white")
{
    $breadimage="images/whitebread.jpg";
}
elseif ($breadtype == "wheat")
{
    $breadimage="images/wheatbread.jpg";
}

$breadoutput="<img src=\"$breadimage\" />";

switch ($size) {
case "small":
    $slices=2;
    break;
case "medium":
    $slices=4;
    break;
case "large":
    $slices=6;
    break;
}

$sizeoutput=$slices ." slices of";

switch ($meattype) {
case "ham":
    $meatimage="images/ham.jpg";
    break;
case "turkey":
    $meatimage="images/turkey.jpg";
    break;
case "beef":
    $meatimage="images/turkey.jpg";
    break;
case "salami":
    $meatimage="images/salami.jpg";
    break;
}

$meatoutput="<img src=\"$meatimage\" />";

$switch ($cheesetype) {
case "american":
    $cheeseimage="images/american.jpg";
    break;
case "swiss":
    $cheeseimage="images/swiss.jpg";
    break;
case "jack":
    $cheeseimage="images/jack.jpg";
    break;
}

$cheeseoutput="<img src=\"$cheeseimage\" />";

foreach ($extras as $extra)
{
    $ei="images/" .$extra .".jpg";

    $extrasimage .= "<br/><img src=\"$ei\"/>";
}

$extrasoutput="and " .$extrasimage;

foreach ($condiments as $condiment)
{
    $ci="images/" .$condiment .".jpg";

    $condimentsimage .= "<br/><img src=\"$ci\"/>";
}

$condimentsoutput="and " .$condimentsimage;

echo $breadoutput;
echo "<br>";
echo $sizeoutput;
echo "<br>";
echo $meatoutput;
echo "<br>";
echo $cheeseoutput;
echo "<br>";
echo $extrasoutput;
echo "<br>";
echo $condimentsoutput;
?>
4

2 回答 2

3
$switch ($cheesetype) {

应该

switch ($cheesetype) {

放下$标志。

于 2013-09-12T23:23:11.813 回答
0

它应该是 switch 而不是 $switch

于 2013-09-13T01:03:49.227 回答