好的,所以我真的不知道如何正确地表达标题,所以这应该可以说明情况。
我正在用Java制作一个回文程序。无论您以哪种方式看待它,它都可以正常工作。它使用 读取文件Scanner
,搜索整个文件并输出文本文件中的该行是否为回文。如果您有任何特殊字符或大写字母,它会删除它们并将所有内容转换为小写。
我的问题是,在每行完成检查后,我想在结果旁边显示一些额外的信息。
每行应显示该行中有多少个单词,多少个字符以及是否为回文。
无论如何这里是代码,希望有人可以帮助我解决这个问题。谢谢。
import java.io.File;
import java.util.Scanner;
public class Palindrome {
public static void main(String[] args) {
//Global Variables
Scanner cScan = null;
Scanner wScan = null;
Scanner pScan = null;
int charCount = 0, numLines = 0, numChars = 0, wordCount = 0;
//Take in User Input
Scanner iScan = new Scanner(System.in); //Start input Scanner
String fileName = null;
System.out.print("Please Enter a File Name: ");
fileName = iScan.nextLine();
iScan.close(); //Close input Scanner
//Read File Specified by User
File palin = new File(fileName);
try {
//Checks for Number of Characters
cScan = new Scanner(palin);
while(cScan.hasNextLine()) {
String line = cScan.nextLine();
numChars += line.length();
numLines++;
}
//Checks for Number of Words
wScan = new Scanner(palin);
while (wScan.hasNext()) {
wScan.next();
wordCount++;
}
//Format Lines
pScan = new Scanner(palin);
while (pScan.hasNext()) {
String line = pScan.nextLine();
String reString = line.replaceAll("[^\\p{L}\\p{Nd}]", "");
String lString = reString.toLowerCase();
boolean pali = false;
String tP = "Yes", fP = "No";
int n = lString.length();
for (int i = 0; i < (n / 2) + 1; ++i) {
if (lString.charAt(i) != lString.charAt(n - i - 1)) {
pali = false;
break;
}
else if (lString.charAt(i) == lString.charAt(n - i - 1)) {
pali = true;
break;
}
}
if (pali == true)
System.out.println(line + " w: " + wordCount + ", " + " c: " + charCount + ", " + tP);
else
System.out.println(line + " w: " + wordCount + ", " + " c: " + charCount + ", " + fP);
}
}
catch(Exception e) {
System.out.println("File Could Not be Found");
}
//charCount = (numLines + numChars) - 1; //Minus 1 to Compensate for EOL at EOF
//System.out.println(charCount);
//System.out.println(wordCount);
//System.out.println(spRemover);
}
}