regex - RegExp：匹配不包含给定单词的字符串

Question

我想检查一个字符串是否不包含字符串，例如：

str1 = "He is a minion, he's so funny."
str2 = "He is not a minion, he's funny."
str3 = "He is not a minion, he's also funny."

我需要检查哪个字符串不包含notand also。所以，预期的结果是：str1is false, str2is false, str3is true。

什么是正则表达式？

Answer 1

您可以使用一系列前瞻：

(?=.*not)(?=.*also).*

Answer 2

您也可以在没有前瞻的情况下解决此问题。使用x修饰符使正则表达式更易于理解。

/.*? \b not \b .*? \b also \b | .*? \b also \b .* \b not \b/x 

Answer 3

要查找包含多个单词的行，请向前看

(?=.*\bnot\b)(?=.*\balso\b).*

正则表达式：

(?=           look ahead to see if there is:
 .*          any character except \n (0 or more times)
 \b           the boundary between a word char and something that is not a word char
  not         'not'
 \b           the boundary between a word char and something that is not a word char
)             end of look-ahead
(?=           look ahead to see if there is:
 .*          any character except \n (0 or more times)
 \b           the boundary between a word char and something that is not a word char
  also         'also'
 \b           the boundary between a word char and something that is not a word char
)             end of look-ahead
.*            any character except \n (0 or more times)

现场演示