假设我们有两个热可观察的整数，我们得到一个像这样的结果
var result = Observable.Zip(observable1, observable2);
我的问题是，假设一个元素来自 observable1，结果是在调用观察者之前等待 observable2 中的匹配对还是从观察者 2 获取最后一个值？
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Zip waits for a pair to come through.
If you want to use the latest value from observer2 when a value comes through observable1, you should use CombineLatest.
You can also find more info on combining sequences in the Intro to Rx chapter on that topic.
于 2013-09-12T16:05:30.920 回答