大家好,喜欢 RAILS 的每个人,我有一个问题,我试图通过“ejecutive_id”导出到 XLS,但我没有做正确的代码,
-I created a select box where i can select all my ejecutives.
-I created another select box where i can select by status_id.
-I selected 1 ejecutive for example "Mogan" (ejecutive_id = 1)
-I selected 1 status form example "active" (status_id = 0 )
-After selecting both select boxes i click on "SEARCH"
-After doing SEARCH i'm getting my results (@list_policies this value in my code is before respond format)
这是我的控制器
****PROJECT/APP/CONTROLLER/policy_managment/policy.rb********
class PolicyManagement::PolicyController < ApplicationController
def generate_print_ejecutive_comercial
@search_ejecutive = params[:search_ejecutive]
@search_status = params[:status_id]
@list_ejecutives_comision = Ejecutive.find(:all)
@list_policies_search = Policy.deleted_is(0)
if params[:search_ejecutive].to_i!=0
@list_policies_search = @list_policies_search.ejecutive_id_is(@search_ejecutive)
end
if !params[:status_id].blank?
if params[:status_id].to_i != 3
@list_policies_search = @list_policies_search.state_is(params[:status_id])
end
else
@list_policies_search = @list_policies_search.state_is(0)
end
@status_id = params[:status_id]
if !@search_dependent_dni.blank?
if @list_dependents.blank?
@list_dependents = Dependent.id_gt(0)
end
@list_dependents = @list_dependents.num_document_is(@search_dependent_dni)
list_dependencies = []
@list_dependents.each do |dependent|
list_dependency_dependents = Dependency.find(:all, :conditions => { :dependent_id => dependent.id })
list_dependency_dependents.each do |dependency|
list_dependencies << dependency
end
end
policy_ids = []
list_dependencies.each do |dependency|
policy_ids << dependency.policy_id.to_i
end
end
@list_policies_search = @list_policies_search.deleted_is(0)
@list_policies = @list_policies_search.paginate(:page => params[:page], :per_page => 10)
respond_to do |format|
format.html
format.xls
format.js {
render :update do |page|
page.replace_html 'table', :partial => 'table2'
end
}
end
end
end
这可能是问题所在,这些也是我可以导出的链接
*********HERE IS MY VIEW***********
<% form_remote_tag :url=>{:action=>"generate_print_ejecutive_comercial"},:before=>"load_close('loading_search')",:success=>"load_off('loading_search')" do -%>
<label>Ejecutive:</label>
<%= select_tag 'search_ejecutive',"<option value=\"\">Seleccione</option>"+options_for_select(@list_ejecutives_comision.collect {|t| [t.name.to_s+" "+t.lastname1.to_s,t.id]})%>
</span>
<%= hidden_field_tag :order,@order %>
<%= hidden_field_tag :page,1 %>
<input name="Buscar" value="SEARCH" type="submit" /><span id="loading_search"></span>
<% end %>
#HERE WITH THOSE LINKS I'M EXPORTING ONLY MY FIRST 10 VALUES
<%= link_to("Export Excel","http://localhost:3000/policy_management/policy/generate_print_ejecutive/generate_print_ejecutive_comercial.xls")%>
<%= link_to "Export XLS",:controller=>"policy_management/policy",:action=>"generate_print_ejecutive_comercial",:format=>"xls" %>
<%= link_to 'PRINT PDF', :controller=>"policy_management/policy",:action=>"generate_print_ejecutive_comercial", :format=>"pdf" %>
我正在导出我的部分视图,这取决于
@list_policies = @list_policies_search.paginate(:page => params[:page], :per_page => 10)
这是我的部分观点,我正在使用@list_policies
********************PARTIAL VIEW THAT I WANT TO EXPORT*********
<table>
<% @list_policies.each do |policy| %>
<tr>
<td><div class="nobreak"><%= policy.num_policy%></div></td>
<td><div class="nobreak">
<% if !policy.ejecutive.blank? %>
<%= policy.ejecutive.name %><%= policy.ejecutive.lastname1 %><%= policy.ejecutive.lastname2 %>
<% end %></div>
</td>
<td><div class="nobreak"><%= policy.str_state%></div></td>
</tr>
</table>
当我添加这个@results 并在我的部分视图中替换它时,我得到了一切,但我不想要一切,我只想要 ejecutive_id
@list_policies = @list_policies_search.paginate(:page => params[:page], :per_page => 10)
@results = @list_policies_search.find(:all)
有人可以帮我吗?我将非常感谢所有帮助