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我开始玩弄 Leap Motion Controller 并在 Swing 中制作了一个小的 GUI。这意味着它只是一个带有标签的框架，它应该显示 Leap Motion 看到的文本。不幸的是，我的程序在两秒钟后就崩溃了。我没有例外或类似的东西。这是我的代码：

public class GUI extends JFrame{
private static final long serialVersionUID = 6411499808530678723L;

public JLabel label;

public GUI(){
    this.setDefaultCloseOperation(EXIT_ON_CLOSE);
    this.setSize(300, 200);
    this.label = new JLabel("Waiting for Gestures");
    this.add(label);

    setVisible(true);
}

public class LeapListener extends Listener{
    JLabel label;

    LeapListener(JLabel label){
        this.label = label;
    }

    @Override
    public void onInit(Controller controller){

    }

    @Override
    public void onExit(Controller controller){

    }

    @Override
    public void onConnect(Controller controller){
        System.out.println("bin da");
        controller.enableGesture(Gesture.Type.TYPE_CIRCLE);
        controller.enableGesture(Gesture.Type.TYPE_KEY_TAP);
        controller.enableGesture(Gesture.Type.TYPE_SCREEN_TAP);
        controller.enableGesture(Gesture.Type.TYPE_SWIPE);
    }

    @Override
    public void onDisconnect(Controller controller){

    }

    @Override
    public void onFrame(Controller controller){
        Frame frame = controller.frame();

        GestureList glist = frame.gestures();

        for (int i = 0; i < glist.count(); i++){
            Gesture g = glist.get(i);

            switch (g.type()){
            case TYPE_CIRCLE:
                CircleGesture circle = new CircleGesture(g);
                this.label.setText("Mach mal nen Kreis!");
            case TYPE_KEY_TAP:
                KeyTapGesture key = new KeyTapGesture(g);
                this.label.setText("Schreiben?");
            case TYPE_SCREEN_TAP:
                ScreenTapGesture screen = new ScreenTapGesture(g);
                this.label.setText("Klicken?");
            case TYPE_SWIPE:
                SwipeGesture swipe = new SwipeGesture(g);
                this.label.setText("Da wurde gewischt!");
            default:
                System.out.println("nothing!");
            break;
            }
        }
    }
}

public static void main(String[] args) {
    GUI gui = new GUI();
    LeapListener listener;
    listener = gui.new LeapListener(gui.label);
    Controller controller = new Controller();
    controller.addListener(listener);

}

}

我不知道我做错了什么。Windows-Error-Message 表示 Java Platform SE 二进制文件已关闭 (javaw.exe)。Errormodule: Leap.dll 是我犯的错误还是我的整个设置都搞砸了？

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1 回答 1

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Ok, I found a solution by myself but unfortunately I can't explain it.
I have to create the Controller Object in the class declaration, not in the main-method. Then I have to add the listener to the controller in the constructor of my GUI, like that:

public class GUI extends JFrame{
private static final long serialVersionUID = 6411499808530678723L;

public JLabel label;
public Controller c = new Controller();
public LeapListener listener;

public GUI(){
    this.setDefaultCloseOperation(EXIT_ON_CLOSE);
    this.setSize(300, 200);
    this.label = new JLabel("Waiting for Gestures");
    this.add(label);
    listener = new LeapListener(this.label);
    c.addListener(listener);
    setVisible(true);
}
    ...
}

So, I'm happy that I got it to work but maybe somebody is interested in the problem and may find a reason for the error I've had.

于 2013-09-12T13:20:23.310 回答