我正在使用 python 并在大学做家庭作业，因为这个我不能让 if-elif-else 函数工作.. D:
这是我的代码，我无法让它正常工作。它只打印没什么可吹嘘的。即使分数是1000。
score = raw_input("What is your score?")
if (score >= 0, score <= 999):
print "Nothing to brag about."
elif (score >= 1000, score <= 9999):
print "Good Score."
elif (score >= 10000):
print "Very Impressive!"
else:
print "That's not a legal score!"
首先，您不需要那些括号；
其次，您需要使用and代替,；
第三，您需要将输入转换为，int因为raw_input函数返回一个string.
如果您help(raw_input)在交互式终端中输入，您应该会看到定义：
raw_input(...)
raw_input([prompt]) -> string
固定代码：
score = int(raw_input("What is your score?"))
if score >= 0 and score <= 999:
print "Nothing to brag about."
elif score >= 1000 and score <= 9999:
print "Good Score."
elif score >= 10000:
print "Very Impressive!"
else:
print "That's not a legal score!"
您可以使用and运算符正确地执行逻辑，或者更好地a<b<c使用 Python 中布尔值的语法。逗号通常表示 Python 中的元组。也不要忘记将您的输入转换为int.
score = int(raw_input("What is your score?"))
if 0 <= score <= 999:
print "Nothing to brag about."
elif 1000 <=score <= 9999:
print "Good Score."
elif score >= 10000:
print "Very Impressive!"
else:
print "That's not a legal score!"
首先，您需要将结果raw_input()转换为整数。
其次，Python 不会在比较器周围使用方括号。您拥有的结构是带有布尔值的元组，这会导致意想不到的结果。
最后，Python 可以将比较器链接在一起以生成更具可读性的代码。
score = raw_input("What is your score?")
try:
score = int(score)
except:
# Casting a non-number to an integer will throw an expection.
# You need to handle that in some way that makes sense.
score = -1 # Setting the score to -1 will at least cause the else branch to fire.
if 0 <= score <= 999:
print "Nothing to brag about."
elif 1000 <= score <= 9999:
print "Good Score."
elif score >= 10000:
print "Very Impressive!"
else:
print "That's not a legal score!"
尝试这个：
score = raw_input("What is your score?")
if ( int(score) <= 999 and int(score) >= 0):
print "Nothing to brag about."
elif (int(score) >= 1000 and int(score) <= 9999):
print "Good Score."
elif (int(score) >= 10000):
print "Very Impressive!"
else:
print "That's not a legal score!"