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基本上，我从大学得到了家庭作业，用户必须输入 x 盎司的数量，所有这些都会被转换并以石头、磅和剩余盎司的形式打印到屏幕上。我已经坚持了将近一个星期。这是到目前为止我设法完成的代码：

inp = int(input("Enter your weight in ounces: "))

stones = int(inp / 224)
inp1 = int(inp - (stones * 14))
pounds = int(inp1 % 16)

print(stones ,"Stones", pounds, "Pounds")

石头钻头工作得很好，但我想知道你是如何得到剩余的盎司并将它们转换成磅然后剩下的盎司？

4

2 回答 2

1

更好的方法是先将盎司转换为磅，然后再将磅转换为石头。

def convert(total_ounces):
    ounces = total_ounces % 16
    total_pounds = total_ounces//16      # 1 pound = 16 ounces
    pounds = total_pounds % 14
    stones = total_pounds//14            # 1 stone = 14 pounds
    print stones, " stones ", pounds, "pounds", ounces, " ounces"


>>> convert (110)
    0  stones  6 pounds 14  ounces

>>> convert (500)
    2  stones  3 pounds 4  ounces

以及您的代码存在的问题：

inp = int(input("Enter your weight in ounces: "))

stones = int(inp / 224)                    # Here you get the maximum no of stones. You 
                                           # should better be using inp // 224 rather 
                                           # that int(inp / 224).
inp1 = int(inp - (stones * 14))            # Firstly, since both inp and stones*14 would      
                                           # be int so there is no need for using int(). 
                                           # and what I think you are trying to do here  
                                           # is finding the remaining no of ounces, so 
                                           # you should be doing something like
                                           # inp1 = inp - stones * 14 * 16
pounds = int(inp1 % 16)                    # again here there is no need of using int. 
                                           # And inp1 % 16 should return the number of 
                                           # ounces not pounds. Pounds should be inp1 // 16 .


print(stones ,"Stones", pounds, "Pounds")
于 2013-09-11T14:10:51.740 回答
0

你和你的很亲近。这有效：

inp = float(input("Enter your weight in ounces: "))

stones = inp / 224
pounds = stones * 14

print('{:.2f} Ounces is {:.2f} Stones or {:.2f} Pounds'.format(inp, stones, pounds))

但是，由于石头传统上用有理数而不是小数表示，您可以使用标准 Python 库中的Fractions模块：

import fractions

inp = int(input("Enter your weight in ounces: "))

if inp>=14*16:
    stones, f=inp // 224, fractions.Fraction(inp%224, inp)
    pounds, oz = inp // 16, inp%16
    outs=str(stones)
    if abs(f)>.01:
        outs+=' and {}/{}'.format(f.numerator, f.denominator)

    outs+=' Stone'   
    outs+=' or {} Pounds'.format(pounds)
    if oz>=1:
        outs+=' {} ounces'.format(oz)    
    print(outs)

else:
    f=fractions.Fraction(inp, 224)
    pounds, oz = inp // 16, inp%16

    print('{}/{} Stone or {} Pounds {} ounces'.format(
          f.numerator, f.denominator, pounds, oz))

示例输入、输出：

Enter your weight in ounces: 1622
7 and 27/811 Stone or 101 Pounds 6 ounces

Enter your weight in ounces: 17
17/224 Stone or 1 Pounds 1 ounces

Enter your weight in ounces: 2240
10 Stone or 140 Pounds

Enter your weight in ounces: 3450
15 and 3/115 Stone or 215 Pounds 10 ounces

或者你可以用传统的英国方式打印石头重量N Stone XX (pounds)：

inp = int(input("Enter your weight in ounces: "))
print('{} Stone {}'.format(inp//224, inp%224//16))

哪个打印：

Enter your weight in ounces: 2528
11 Stone 4
于 2013-09-11T21:18:49.157 回答