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我有一对函数，简单地说，检索 bimap 的左/右值并打印一条消息（或者，取决于函数的 bool arg，导致程序中的致命错误）：

#ifdef __cplusplus
template<typename Lt, typename Rt>
Rt Q_bimapleft( boost::bimap<Lt, Rt> themap, Lt L, bool throwError = false )
{
    try
    {
        Rt returnVal = themap.left.at(L);
        return returnVal;
    }
    catch( ... )
    {
        if( throwError )
        {
            Com_Error(ERR_FATAL, "Q_bimapright failure on lookup of %s\n", boost::lexical_cast<char *, Lt>(L));
        }
        else
        {
            Com_Printf(S_COLOR_YELLOW "WARNING: Q_bimapright failure on lookup of %s\n", boost::lexical_cast<char *, Lt>(L));
        }
    }
    return (Rt)-1;
}

template<typename Lt, typename Rt>
Lt Q_bimapright( boost::bimap<Lt, Rt> themap, Rt R, bool throwError = false )
{
    try
    {
        Lt returnVal = themap.right.at(R);
        return returnVal;
    }
    catch( ... )
    {
        if( throwError )
        {
            Com_Error(ERR_FATAL, "Q_bimapleft failure on lookup of %s\n", boost::lexical_cast<char *, Rt>(R));
        }
        else
        {
            Com_Printf(S_COLOR_YELLOW "WARNING: Q_bimapleft failure on lookup of %s\n", boost::lexical_cast<char *, Rt>(R));
        }
    }
    return (Lt)-1;
}
#endif

但是，当我去使用该功能时：

....
boost::bimap<int, std::string> animTable;
char token[1024];
....
int index = Q_bimapleft<int, std::string>(animTable, token);

Intellisense/编译器报告：

IntelliSense: no instance of function template "Q_bimapleft" matches the argument list
4

1 回答 1

2 
Q_bimapleft<int, std::string>(animTable, token);

必须有签名

(boost::bimap<int, string> themap, std::string)

不是

(boost::bimap<int, string> themap, int)

换句话说，你试图char*通过int

于 2013-09-11T03:52:42.750 回答