ruby - 基于模式匹配从数组中生成包含元素的字符串

Question

我有一个这样的数组：

inList = ["edge_rabbit", "nsp_edge_rabbit", "services", "syslog", "master_rabbit", "mongod", ...]

如何获取以_rabbitformat 结尾的元素或元素mongo[cds]，并生成一个逗号分隔的字符串，如下所示？

"edge_rabbit, nsp_edge_rabbit, master_rabbit"

Answer 1

这是您正在寻找使用String#end_with?and的那个Array#select吗？

inList = ["edge_rabbit", "nsp_edge_rabbit", "services", "syslog", "master_rabbit", "mongod"]
inList.select{|e| e.end_with?('_rabbit')}.join(", ")
# => "edge_rabbit, nsp_edge_rabbit, master_rabbit"

或者

inList = ["edge_rabbit", "nsp_edge_rabbit", "services", "syslog", "master_rabbit", "mongod"]
inList.grep(/_rabbit$/).join(", ")
# => "edge_rabbit, nsp_edge_rabbit, master_rabbit"


inList = ["edge_rabbit","_rabbit_ut", "nsp_edge_rabbit", "services", "syslog", "master_rabbit", "mongod","mongos","mongoy"]
inList.grep(/_rabbit$|^mongo[cds]/).join(", ")
# => "edge_rabbit, nsp_edge_rabbit, master_rabbit, mongod, mongos"

Answer 2

我会使用一些小模式：

in_list = ["edge_rabbit", "nsp_edge_rabbit", "services", "syslog", "master_rabbit", "mongod"]

in_list.select{ |s| s[/(?:^mongo)|(?:_rabbit$)/] }.join(', ') # => "edge_rabbit, nsp_edge_rabbit, master_rabbit, mongod"

或者：

in_list.grep(/(?:^mongo)|(?:_rabbit$)/).join(', ') # => "edge_rabbit, nsp_edge_rabbit, master_rabbit, mongod"

如果除,或mongo之外的其他尾随字符可能有变化，请使用：cds

in_list.grep(/(?:^mongo[cds])|(?:_rabbit$)/).join(', ') # => "edge_rabbit, nsp_edge_rabbit, master_rabbit, mongod"