由于您可以控制模型，因此文档在此处有一个示例。

将您的模型转换为如下所示：

var animals = [
    {name: "great dane", subcat: "Dogs"},
    {name: "lab",        subcat: "Dogs"},
    {name: "tabby",      subcat: "Cats"},
    {name: "black",      subcat: "Cats"}
];
// and put it in the $scope
$scope.animals = animals;

选择看起来像：

<select ng-model="..." ng-options="a.name group by a.subcat for a in animals">

选择将是具有name和subcat属性的整个动物对象。

无需展平数据的替代方法是使用嵌套ng-repeat指令，如本文所述。

<div ng-repeat="people in People">
<label>{{people.firstName}}</label>
<select>
<option ng-repeat-start="choice in people.Choices" ng-bind="choice.Name"></option>
<option ng-repeat-end ng-repeat="opt in choice.Options" ng-bind="' - ' + opt.Name"></option>
</select>
</div>

http://plnkr.co/edit/2vj4PK?p=preview