1

这段代码：

SELECT  
    O896IA_VEMPPRSA.REG_NR & O896IA_VEMPPRSA.DIS_NR AS RRDD,  
    Mgmt_Lvl.MGMT_LVL,  
    Count(O896IA_VEMPPRSA.SYS_EMP_ID_NR) AS Total,  
    Sum(IIf(emp_rlc_ir="Y",1,0)) AS Relocate,  
    Sum(IIf(emp_int_asn_ir="Y",1,0)) AS International_Assignment,  
    Sum(IIf(emp_tvl_ir="y",1,0)) AS Travel,  
    Sum(IIf(emp_spc_asn_ir="y",1,0)) AS Special_Assignment,  
    Sum(IIf([emp_rlc_ir]="Y",1,0))/[Total] AS Relocate_Percent,  
    Sum(IIf([emp_int_asn_ir]="Y",1,0))/[Total] AS International_Assignment_Percent,  
    Sum(IIf([emp_tvl_ir]="y",1,0))/[Total] AS Travel_Percent,  
    Sum(IIf([emp_spc_asn_ir]="y",1,0))/[Total] AS Special_Assignment_Percent

FROM (O867IA_VPJOBCO INNER JOIN Mgmt_Lvl  
    ON O867IA_VPJOBCO.JOB_GRP_CD = Mgmt_Lvl.JOB_GRP_CD)  
INNER JOIN (O896IA_VEMPPRSA INNER JOIN O867IA_VCAREER  
    ON O896IA_VEMPPRSA.SYS_EMP_ID_NR = O867IA_VCAREER.SYS_EMP_ID_NR)  
    ON O867IA_VPJOBCO.JOB_CLS_CD = O896IA_VEMPPRSA.JOB_CLS_CD

WHERE (((O896IA_VEMPPRSA.EMP_EMT_STS_CD)<>"T"))

GROUP BY  
    O896IA_VEMPPRSA.REG_NR & O896IA_VEMPPRSA.DIS_NR, 
    Mgmt_Lvl.MGMT_LVL,  
    Mgmt_Lvl.Ranking

ORDER BY Mgmt_Lvl.Ranking DESC;

给我员工的调查答案，问题是这项调查每年都会进行，我需要最近几年的答案。

我尝试将 MAX 用于 REC_EFF_STT_DT 但对于某些员工来说，他们的答案每年都会发生变化，因此由于 group by （我需要）它仍然返回多年的答案。

有没有一种解决方案，我可以只提取最新数据？如果员工在 2008 年、2009 年和 2010 年而不是在 2011 年、2012 年或 2013 年参加调查，则不一定必须是 2013 年，那么我仍然想要 2010 年的数据，无论他们参加的最新调查是什么我需要。

4

1 回答 1

1

假设您有一个名为 [Survey] 的表，其中包含以下数据

RespondentID    SurveyDate  Answer1                         Answer2
------------    ----------  ----------------------------    ----------------------------
1               2013-01-01  answer 1, respondent 1, 2013    answer 2, respondent 1, 2013
1               2012-01-01  answer 1, respondent 1, 2012    answer 2, respondent 1, 2012
2               2012-01-01  answer 1, respondent 2, 2012    answer 2, respondent 2, 2012

您可以使用表单的查询...

SELECT Survey.*
FROM
    Survey
    INNER JOIN
    (
        SELECT RespondentID, MAX(SurveyDate) AS MaxOfSurveyDate
        FROM Survey
        GROUP BY RespondentID
    ) AS MaxDate
        ON Survey.RespondentID = MaxDate.RespondentID
            AND Survey.SurveyDate = MaxDate.MaxOfSurveyDate

...返回每个受访者的最新行，在本例中为：

RespondentID    SurveyDate  Answer1                         Answer2
------------    ----------  ----------------------------    ----------------------------
1               2013-01-01  answer 1, respondent 1, 2013    answer 2, respondent 1, 2013
2               2012-01-01  answer 1, respondent 2, 2012    answer 2, respondent 2, 2012
于 2013-09-10T17:30:01.283 回答