0

我想知道当我们从 url 导航到新 url 时如何在 webview 中调用进度对话框。请提供一个示例或片段来说明如何实现这一点。非常感谢。

4

3 回答 3

1

您可以在 onCreate() 方法上使用它：

    web = (WebView) findViewById(R.id.webview01);
    progressBar = (ProgressBar) findViewById(R.id.progressBar1);

    web.setWebViewClient(new myWebClient());
    web.getSettings().setJavaScriptEnabled(true);
    web.loadUrl("http://www.google.com");

然后使用

    public class myWebClient extends WebViewClient
   {
    @Override
    public void onPageStarted(WebView view, String url, Bitmap favicon) {
        // TODO Auto-generated method stub
        super.onPageStarted(view, url, favicon);
    }

    @Override
    public boolean shouldOverrideUrlLoading(WebView view, String url) {
        // TODO Auto-generated method stub

        view.loadUrl(url);
        return true;

    }

    @Override
    public void onPageFinished(WebView view, String url) {
        // TODO Auto-generated method stub
        super.onPageFinished(view, url);

        progressBar.setVisibility(View.GONE);
    }
    }

   // To handle "Back" key press event for WebView to go back to previous screen.
   @Override
   public boolean onKeyDown(int keyCode, KeyEvent event)
   {
    if ((keyCode == KeyEvent.KEYCODE_BACK) && web.canGoBack()) {
        web.goBack();
        return true;
    }
    return super.onKeyDown(keyCode, event);
  }
  }
于 2013-09-10T04:57:41.617 回答
0

试试这个网站，它可能会解决你的问题

http://www.javacodegeeks.com/2012/03/android-load-webview-with-progressbar.html

于 2013-09-10T04:56:16.143 回答
0

试试这个可能对你有帮助

web = (WebView) findViewById(R.id.webview01);
    progressBar = (ProgressBar) findViewById(R.id.progressBar1);

    web.setWebViewClient(new myWebClient());
    web.getSettings().setJavaScriptEnabled(true);

    web.setWebChromeClient(new WebChromeClient() {
        public void onProgressChanged(WebView view, int progress) {
            if(progress<100){
                //show progress
            }else{
                //hide progress
            }
        }
    });
    web.setWebViewClient(new WebViewClient());
    web.getSettings().setJavaScriptEnabled(true);
    web.getSettings().setPluginState(PluginState.ON);
    web.loadUrl("http://www.google.com");
于 2013-09-10T05:01:49.307 回答