背景
我正在开发 Bukkit 插件（Minecraft 服务器端）。该插件允许玩家来回发送消息。我也在开发一个网络界面。为了查看他们的“收件箱”，他们必须首先使用游戏中设置的密码登录。
这个密码不是原始存储的，它被转换成一长串 unicode 值，然后分成几块，每块都转换为十六进制并附加到不同的字符串。
爪哇版
//This isn't the best method, I know, but it's still going to take a genius to crack it.
//The resulting number (before somewhat converted to hex) is really
//long, there isn't an easy way of knowing the sequence of characters.
//This conversion is much different than straight up converting to hex,
//as PHP has certain limitations
public static String encodePassword(String password) {
String longNumber = "";
for(int i = 0; i < password.length(); i++) {
longNumber += ((int) password.charAt(i));
}
//System.out.println("long = " + longNumber);
String result = "";
int splitLength = 5;
int iterations = longNumber.length() / splitLength;
if(longNumber.length() % splitLength > 0)
iterations++;
for(int i = 0; i < iterations; i++) {
//System.out.println(result);
int start = splitLength * i;
if(longNumber.length() - start <= splitLength) {
String sub = longNumber.substring(start);
result += Integer.toHexString(Integer.parseInt(sub));
continue;
}
String sub = longNumber.substring(start, start + splitLength);
result += Integer.toHexString(Integer.parseInt(sub));
}
return result;
}
PHP版本
function encodePassword($pw){
$unicode = "";
for($i=0; $i<strlen($pw); $i++){
$char = $pw{$i};
$val = unicode_value($char);
$unicode = $unicode.$val;
}
$result = "";
$splitLength = 5;
$iterations = strlen($unicode) / $splitLength;
if(strlen($unicode) % $splitLength > 0)
$iterations++;
for($i = 0; $i < $iterations; $i++) {
$start = $splitLength * $i;
if(strlen($unicode) - $start <= $splitLength) {
$sub = substr($unicode, $start);
$result = $result.base_convert($sub, 10, 16);
continue;
}
$sub = substr($unicode, $start, $splitLength);
$result = $result.base_convert($sub, 10, 16);
}
return $result;
}
如果我对密码“partychat”（插件的名称，它也具有群聊功能）进行“编码”，我会2c212c93ef23163a91bcc使用 Java 和2c212c93ef23163a91bcc0PHP（除了尾随 0 之外相同）。有什么我做错了吗？
注意： 这并不总是发生，大多数“编码”工作正常，但由于某种原因，这种情况有时会发生