81

下面是我用来将文件上传到目录中的代码。它工作正常。我的主要问题是：

move_uploaded_file()是将上传的文件保存到目录中的那个，我也猜测move_uploaded_file()是为其设置名称的那个。

如何将文件名更改为随机数？

我试图在下面这样做：

$allowedExts = array("gif", "jpeg", "jpg", "png");
$temp = explode(".", $_FILES["file"]["name"]);
$extension = end($temp);
if ((($_FILES["file"]["type"] == "image/gif") || ($_FILES["file"]["type"] == "image/jpeg") || ($_FILES["file"]["type"] == "image/jpg") || ($_FILES["file"]["type"] == "image/pjpeg") || ($_FILES["file"]["type"] == "image/x-png") || ($_FILES["file"]["type"] == "image/png")) && ($_FILES["file"]["size"] < 100000) && in_array($extension, $allowedExts)) {
    if ($_FILES["file"]["error"] > 0) {
        echo "Return Code: " . $_FILES["file"]["error"] . "<br>";
    } else {

        $fileName = $temp[0] . "." . $temp[1];
        $temp[0] = rand(0, 3000); //Set to random number
        $fileName;

        if (file_exists("../img/imageDirectory/" . $_FILES["file"]["name"])) {
            echo $_FILES["file"]["name"] . " already exists. ";
        } else {
            move_uploaded_file($_FILES["file"]["tmp_name"], "../img/imageDirectory/" . $_FILES["file"]["name"]);
            echo "Stored in: " . "../img/imageDirectory/" . $_FILES["file"]["name"];
        }
    }
} else {
    echo "Invalid file";
}

我尝试更改变量，例如$_FILES["file"]["name"]并将其替换为$fileName; 变量，以便可以存储新名称。

4

5 回答 5

179

您可以通过更改文件的第二个参数中的名称来简单地更改文件的名称move_uploaded_file。

代替

move_uploaded_file($_FILES["file"]["tmp_name"], "../img/imageDirectory/" . $_FILES["file"]["name"]);

采用

$temp = explode(".", $_FILES["file"]["name"]);
$newfilename = round(microtime(true)) . '.' . end($temp);
move_uploaded_file($_FILES["file"]["tmp_name"], "../img/imageDirectory/" . $newfilename);

Changed to reflect your question, will product a random number based on the current time and append the extension from the originally uploaded file.

于 2013-09-09T19:40:28.347 回答
6

You guess correctly. Read the manual page for move_uploaded_file. Set the second parameter to whereever your want to save the file.

If it doesn't work, there is something wrong with your $fileName. Please post your most recent code.

于 2013-09-09T19:41:22.837 回答
5

You can Try this,

$newfilename= date('dmYHis').str_replace(" ", "", basename($_FILES["file"]["name"]));

move_uploaded_file($_FILES["file"]["tmp_name"], "../img/imageDirectory/" . $newfilename);
于 2017-09-12T12:53:44.543 回答
5 
/* create new name file */
$filename   = uniqid() . "-" . time(); // 5dab1961e93a7-1571494241
$extension  = pathinfo( $_FILES["file"]["name"], PATHINFO_EXTENSION ); // jpg
$basename   = $filename . "." . $extension; // 5dab1961e93a7_1571494241.jpg

$source       = $_FILES["file"]["tmp_name"];
$destination  = "../img/imageDirectory/{$basename}";

/* move the file */
move_uploaded_file( $source, $destination );

echo "Stored in: {$destination}";
于 2019-10-30T01:07:23.350 回答
1

The move_uploaded_file will return false if the file was not successfully moved you can put something into your code to alert you in a log if that happens, that should help you figure out why your having trouble renaming the file

于 2018-10-31T21:12:33.933 回答