python - Opencv Python显示原始图像

Question

我不知道如何显示包含 640x480 像素信息的原始图像，每个像素 8 位。（灰色图像）

我需要从 np 数组转换为 Mat 格式才能显示图像。

#!/usr/bin/python
import numpy as np
import cv2
import sys
# Load image as string from file/database    
fd = open('flight0000.raw')
img_str = fd.read()
fd.close()

img_array = np.asarray(bytearray(img_str), dtype=np.uint8)

img = ... Conversion to Mat graycolor

cv2.imshow('rawgrayimage', img)
cv2.waitKey(0)

它与 cv、cv2 如此混淆。我已经尝试了一段时间，但我找不到解决方案。

Answer 1

.RAW files are not supported in OpenCV see imread,

But the file can be opened with Python and parsed with Numpy

import numpy as np
fd = open('flight0000.raw', 'rb')
rows = 480
cols = 640
f = np.fromfile(fd, dtype=np.uint8,count=rows*cols)
im = f.reshape((rows, cols)) #notice row, column format
fd.close()

This makes a numpy array that can be directly manipulated by OpenCV

import cv2
cv2.imshow('', im)
cv2.waitKey()
cv2.destroyAllWindows()

Answer 2

#!/usr/bin/python
#code to display a picture in a window using cv2
import cv2

cv2.namedWindow('picture',cv2.WINDOW_AUTOSIZE)
frame=cv2.imread("abc.jpg")
cv2.imshow('picture',frame)
if cv2.waitKey(0) == 27:
        cv2.destroyAllWindows()

Answer 3

如果您想将“原始”图像保存为“png”文件（每个像素为 32 位，彩色图像），这只是一个示例：

import numpy as np
import matplotlib.pyplot as plt

img = np.fromfile("yourImage.raw", dtype=np.uint32)
print img.size #check your image size, say 1048576
#shape it accordingly, that is, 1048576=1024*1024
img.shape = (1024, 1024)

plt.imshow(img)
plt.savefig("yourNewImage.png")