4

有没有一种简单的方法来执行以下操作？

我想通过两条对角线将一个视图分成 4 个：

在此处输入图像描述

所以上面的三角形区域将对应“向上”。其他 3 个将分别对应“左”、“下”、“右”。

这样做最简单或最有效的方法是什么？我曾考虑创建 4 个三角形形状并检测其中的触摸，但也许这将是不必要的？

上下文：用于在地图中移动精灵。

谢谢！

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2 回答 2

1

在我发表评论后，我想为自己模拟一个简单的实现，所以，这里有一个简单的全屏操纵杆，它将根据相对于屏幕中心的触摸位置确定类似基数的方向。

（全屏操纵杆）

我仍在使用 cocos2d-iphone 1.1 ，所以.. 我不确定 v2 是否需要任何模组

FSJoy.h

#import "cocos2d.h"

// Up, Down, Left, Right - directions
typedef enum
{
    DIR_NONE = 0,
    DIR_UP,
    DIR_LEFT,
    DIR_DOWN,
    DIR_RIGHT
} ULDR;

// UpLeft, UpRight, DownLeft, DownRight - boundaries
typedef enum
{
    UL = 135,
    UR = 45,
    DL = 225,
    DR = 315
} ULDR_BOUNDS;


@interface FSJoy : CCLayer
{
    CGPoint origin;
    float angleCurrent;
    BOOL isActive;
}

@property CGPoint origin;
@property float angleCurrent;
@property BOOL isActive;
@end

FSJoy.m

#import "FSJoy.h"

@implementation FSJoy

@synthesize origin, angleCurrent, isActive;

-(id) init
{
    if( (self = [super init]) )
    {
        self.isTouchEnabled = YES;
        CGSize screenSize = [[CCDirector sharedDirector] winSize];
        angleCurrent = 0.0f;
        origin = ccp(screenSize.width / 2.0f, screenSize.height / 2.0f);
        isActive = NO;
    }
    return self;
}

-(void) registerWithTouchDispatcher
{
    [[CCTouchDispatcher sharedDispatcher] addTargetedDelegate:self priority:(INT_MIN - 4) swallowsTouches:YES];
}

-(BOOL) ccTouchBegan:(UITouch *)touch withEvent:(UIEvent *)event
{
    CGPoint touchCurrent = [touch locationInView:[touch view]];
    touchCurrent = [[CCDirector sharedDirector] convertToGL:touchCurrent];    
    angleCurrent = [self determineAngleFromPoint:origin toPoint:touchCurrent];
    [self determineDirectionFromAngle: angleCurrent];
    isActive = YES;
    return YES; // full screen controller, so always return YES
}

-(void) ccTouchMoved:(UITouch *)touch withEvent:(UIEvent *)event
{
    CGPoint touchCurrent = [touch locationInView:[touch view]];
    touchCurrent = [[CCDirector sharedDirector] convertToGL:touchCurrent];
    angleCurrent = [self determineAngleFromPoint:origin toPoint:touchCurrent];
    [self determineDirectionFromAngle: angleCurrent];
}

-(void) ccTouchEnded:(UITouch *)touch withEvent:(UIEvent *)event
{
    isActive = NO;
}

-(void) ccTouchCancelled:(UITouch *)touch withEvent:(UIEvent *)event
{
    [self ccTouchEnded:touch withEvent:event];
}

-(float) determineAngleFromPoint:(CGPoint)from toPoint:(CGPoint)to
{
    float angle = ccpToAngle(ccpSub(to, from));
    if (angle <= 0.0f)
    {
        angle += M_PI * 2.0f;
    }

    angle = CC_RADIANS_TO_DEGREES(angle);

//    NSLog(@"angle is %f", angle);
    return angle;
}

-(ULDR) determineDirectionFromAngle:(float) angle
{
    ULDR dir = DIR_NONE;
    dir = ((angle >= UR) && (angle <= UL)) ? DIR_UP     : dir;
    dir = ((angle >= DL) && (angle <= DR)) ? DIR_DOWN   : dir;
    dir = ((angle >  UL) && (angle <  DL)) ? DIR_LEFT   : dir;
    dir = ((angle >  DR) || (angle <  UR)) ? DIR_RIGHT  : dir;
    NSLog(@"direction is %d", dir);
    return dir;
}

@end

用法只是将操纵杆添加到场景/图层：

FSJoyTest.h

#import "cocos2d.h"
@interface FSJoyTest : CCLayer
@end

FSJoyTest.m

#import "FSJoyTest.h"
#import "FSJoy.h"

@implementation FSJoyTest

-(id) init
{
    if( (self=[super init]) )
    {
        [self addChild: [FSJoy node]];
    }
    return self;
}

@end
于 2013-09-11T17:07:49.813 回答
0

只是一个想法：

创建上面视图大小的图像（不要将其添加到任何视图中，只需将其存储在某处）。图像文件将包含您想要的四个三角形，但用不同的颜色为每个三角形着色（没有渐变！:)）

当您点击视图时，获取触摸位置坐标（如果需要，将其转换为图像坐标）并在同一位置测试图像中的像素颜色。颜色会告诉你按下了哪个三角形。

于 2013-09-07T12:05:31.700 回答