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如何在不首先创建和定义具有结构类型的实际对象的情况下将数据添加到包含 int 键和结构值的映射?基本上我有:

struct myStruct { string name2; int aCnt; std::list<string> theItems; };

// Now I define a map
std::map<string, myStruct> myMap;

// Now I want to add items to myMap.  
mymap["ONE"] = {"TEN", 3, {"p1","p2","p3"}};  // But this doesn't seem to work

// I know I could do something like
myStruct myst;
myst.name2 = "TEN";
myst.aCnt = 3;
...blah blah

mymap["ONE"] = myst;

// But I don't want to have to write all of those lines especially because
// this is being done as an initialization of the map.

谢谢!

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1 回答 1

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如果您使用的是 C++11,则此代码已经可以工作:

#include <iostream>
#include <map>
#include <string>
#include <list>
using namespace std;


struct myStruct { string name2; int aCnt; std::list<string> theItems; };
int main()
{

        // Now I define a map
        std::map<string, myStruct> myMap;

        // Now I want to add items to myMap.
        myMap["ONE"] = {"TEN", 3, {"p1","p2","p3"}};  // But this doesn't seem to work





        return 0;
}

并编译:

burgos@germany:~/test$ g++ struct.cpp -o struct -std=c++11
burgos@germany:~/test$

如果你不这样做,那么你就不走运了,但是所有主要的编译器都应该支持 c++11 初始化——确保你获得了最新版本。

于 2013-09-06T21:19:49.743 回答