mysql - 查找按天分组的超过 1 个订单的客户

Question

我想知道有多少客户下了超过 1 个订单，按天分组。但我想排除已取消的订单。

• 我有一张顾客桌子和顾客

• 我有一个带有订单的 customer_order 表（取消订单时它保留在 customer_order 表中）

• 我有一个order_item表（原来的订单在哪里，还有取消的订单，取消的订单得到一个新的信用订单，原始订单id出现在信用订单的id_credit_order行）

我想要这样的东西：

date  |  no of customers with 1 order  |  no of customers with 2 orders  |  no of customers with 3 order  |  etc.

但是，如果原始订单已被取消，我不想计算！

我现在有这个查询，但绝对不够，有人知道如何得到我的结果吗？谢谢！

SELECT DATE(co.date_order), COUNT(co.id_customer)
FROM customer_order co
GROUP BY DATE(co.date_order)
ORDER BY DATE(co.date_order) DESC;

Answer 1

这个问题有点误导，因为您首先询问拥有多个订单的客户数量，然后询问拥有 1、2、3... 个订单的客户数量。

这里有一些可以给你数字的东西，但不重要。您需要为 o.id 输入正确的列名

Select -- outer query takes each order count and counts how many customers have that many
    co.date_order,
    co.customer_order_count,
    count(*) as customer_count
From (
    Select -- inner query counts how many valid orders each customer has
        o.date_order,
        o.id_customer,
        count(*) as customer_order_count
    From
        customer_order o
    Where
        o.id_credit_order is null and -- rule out credit orders
        not exists ( -- rule out orders with related credit orders
            select
                'x'
            from
                customer_order c
            where
                c.id_credit_order = o.id -- column name isn't mentioned in the question
        )
    Group By
        o.date_order,
        o.id_customer
    ) co
Group By
    co.date_order,
    co.customer_order_count
Order By
    co.date_order desc,
    co.customer_order_count

Answer 2

试试这个。更改 WHERE 以反映您取消订单的方式。

SELECT DATE(co.date_order), COUNT(co.id_customer)
FROM customer_order co
WHERE co.cancelled = 0
GROUP BY DATE(co.date_order)
HAVING COUNT(co.id_customer) > 0
ORDER BY DATE(co.date_order) DESC;

Answer 3

尝试使用 HAVING 子句。

SELECT DATE(co.date_order), COUNT(co.id_customer)
FROM customer_order co
WHERE co.Cancelled = 0
GROUP BY DATE(co.date_order)
HAVING COUNT(co.id_customer) >= 1
ORDER BY DATE(co.date_order) DESC;