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我在 C# 中有一个 WebService，它使用 webapi 并通过一个 url 提供一个 json ，直到确定为止。

public class UsuarioByGroupController : ApiController
{
    // GET api/getusuariobygroup
    public List<DTOUsuario> Get()
    {
        int valor = 0;
        return new RepUsuario().GetUsuarioByGrupo(6, 0, int.MaxValue, null, null, out valor).ToList();
    }

在android中，我有一个“获取”传递url的WebService的方法（此方法适用于另一个应用程序）：

private static final String URI = "http://10.0.2.2:3671/api/";


public static <T> T get(String url, T e) throws Exception {

    String[] json = new WebService().get(URI + url);

    List<T> obj = new ArrayList<T>();

    if (json[0].equals("200")) {
        Gson gson = new Gson();
        JsonParser parser = new JsonParser();
        JsonArray array = parser.parse(json[1]).getAsJsonArray();
        for (int i = 0; i < array.size(); i++) {
            obj.add(gson.fromJson(array.get(i), (Class<T>) e));
        }
        return (T) obj;
    } else {
        throw new Exception(json[1]);
    }
}

但它返回给我以下内容：

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN""http://www.w3.org/TR/html4/strict.dtd">
<HTML><HEAD><TITLE>Bad Request</TITLE>
<META HTTP-EQUIV="Content-Type" Content="text/html; charset=us-ascii"></HEAD>
<BODY><h2>Bad Request - Invalid Hostname</h2>
<hr><p>HTTP Error 400. The request hostname is invalid.</p>
</BODY></HTML>

编辑：

public final String[] get(String url) {

    String[] result = new String[2];
    HttpGet httpget = new HttpGet(url);
    HttpResponse response;

    try {
        response = HttpClientSingleton.getHttpClientInstace().execute(
            httpget);
        HttpEntity entity = response.getEntity();

        if (entity != null) {
            result[0] = String.valueOf(response.getStatusLine()
                .getStatusCode());
            InputStream instream = entity.getContent();
            result[1] = toString(instream);
            instream.close();
        }
    } catch (Exception e) {
        Log.e("NGVL", "Falha ao acessar Web service", e);
        result[0] = "0";
        result[1] = "Falha na rede!";
    }
    return result;
}
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