3

I was searching for parsing a log file and found what I need in this link extract data from log file in specified range of time

But the most useful answer (posted by @Kent):

# this variable you could customize, important is convert to seconds. 
# e.g 5days=$((5*24*3600))
x=$((5*60))   #here we take 5 mins as example

# this line get the timestamp in seconds of last line of your logfile
last=$(tail -n1 logFile|awk -F'[][]' '{ gsub(/\//," ",$2); sub(/:/," ",$2); "date +%s -d \""$2"\""|getline d; print d;}' )

#this awk will give you lines you needs:
awk -F'[][]' -v last=$last -v x=$x '{ gsub(/\//," ",$2); sub(/:/," ",$2); "date +%s -d \""$2"\""|getline d; if (last-d<=x)print $0 }' logFile

I think the error is in the "date +%s -d .... part

is giving the following error:

sh: -c: line 0: unexpected EOF while looking for matching `"'
sh: -c: line 1: syntax error: unexpected end of file
sh: -c: line 0: unexpected EOF while looking for matching `"'
sh: -c: line 1: syntax error: unexpected end of file

I spend lot of time trying to solve before I ask here but didn't find any solution.

The script will be called by the crontab to get the last 1 min log lines and count how many times an ip is listed in one minute so I can detect if it is an attack or not. and this is another task hope that an expert will help giving the needed code here in the same question.(I think it can be solved in 2 lines).

4

2 回答 2

2

问题可能只是你没有引用你的 shell 变量。看：

$ foo='ab cd'

$ awk -v bar="$foo" 'BEGIN{print bar}'
ab cd

$ awk -v bar=$foo 'BEGIN{print bar}'
awk: fatal: cannot open file `BEGIN{print bar}' for reading (No such file or directory)

是的，我知道这是一条不同的错误消息——当你不引用 shell 变量时会发生什么，这取决于变量的值、目录的内容等，其中一些非常糟糕，比如删除每个文件你的文件系统。

所以，引用你的变量：

-v last="$last" -v x="$x"

然后看看你是否还有问题。

顺便说一句，这里是如何使用 GNU awk 和输入文件http://pastebin.com/BXmS4zLn真正解决您的原始问题：

$ cat tst.awk
BEGIN {
    ARGV[ARGC++] = ARGV[ARGC-1]

    mths = "JanFebMarAprMayJunJulAugSepOctNovDec"

    if (days)  { hours = days * 24  }
    if (hours) { mins  = hours * 60 }
    if (mins)  { secs  = mins * 60  }
    deltaSecs = secs
}

NR==FNR {
    nr2secs[NR] = mktime($6" "(match(mths,$5)+2)/3" "$4" "gensub(/:/," ","g",$7))
    next
}

nr2secs[FNR] >= (nr2secs[NR-FNR] - deltaSecs)

$ awk -v hours=1 -f tst.awk file
157.55.34.99 - -  06 Sep 2013 09:13:10 +0300  "GET /index.php HTTP/1.1" 200 16977 "-" "Mozilla/5.0 (compatible; bingbot/2.0; +http://www.bing.com/bingbot.htm)"
85.163.134.149 - -  06 Sep 2013 09:50:23 +0300  "GET /wap/wapicons/mnrwap.jpg HTTP/1.1" 200 1217 "http://mydomain.com/main.php" "Mozilla/5.0 (Linux; U; Android 4.1.2; en-gb; GT-I9082 Build/JZO54K) AppleWebKit/534.30 (KHTML, like Gecko) Version/4.0 Mobile Safari/534.30"
83.113.48.218 - -  06 Sep 2013 10:13:07 +0300  "GET /english/nicons/word.gif HTTP/1.1" 200 803 "http://mydomain.com/french/details.php?eid=127928&cid=18&fromval=1&frid=18" "Mozilla/5.0 (compatible; MSIE 9.0; Windows NT 6.0; Trident/5.0)"

$ gawk -v mins=60 -f tst.awk file
157.55.34.99 - -  06 Sep 2013 09:13:10 +0300  "GET /index.php HTTP/1.1" 200 16977 "-" "Mozilla/5.0 (compatible; bingbot/2.0; +http://www.bing.com/bingbot.htm)"
85.163.134.149 - -  06 Sep 2013 09:50:23 +0300  "GET /wap/wapicons/mnrwap.jpg HTTP/1.1" 200 1217 "http://mydomain.com/main.php" "Mozilla/5.0 (Linux; U; Android 4.1.2; en-gb; GT-I9082 Build/JZO54K) AppleWebKit/534.30 (KHTML, like Gecko) Version/4.0 Mobile Safari/534.30"
83.113.48.218 - -  06 Sep 2013 10:13:07 +0300  "GET /english/nicons/word.gif HTTP/1.1" 200 803 "http://mydomain.com/french/details.php?eid=127928&cid=18&fromval=1&frid=18" "Mozilla/5.0 (compatible; MSIE 9.0; Windows NT 6.0; Trident/5.0)"

$ gawk -v mins=20 -f tst.awk file
83.113.48.218 - -  06 Sep 2013 10:13:07 +0300  "GET /english/nicons/word.gif HTTP/1.1" 200 803 "http://mydomain.com/french/details.php?eid=127928&cid=18&fromval=1&frid=18" "Mozilla/5.0 (compatible; MSIE 9.0; Windows NT 6.0; Trident/5.0)"

您可以指定 days= 或 hours= 或 mins= 或 secs= 变量，它会做正确的事情。

如果您只需要一个脚本来获取您的问题所述的最后 1 分钟的日志行（现在？），并且希望看到一个单行来执行此操作：

$ gawk 'NR==FNR {nr2secs[++nr] = mktime($6" "(match("JanFebMarAprMayJunJulAugSepOctNovDec",$5)+2)/3" "$4" "gensub(/:/," ","g",$7)); next} nr2secs[FNR] >= (nr2secs[nr] - 60)' file file
83.113.48.218 - -  06 Sep 2013 10:13:07 +0300  "GET /english/nicons/word.gif HTTP/1.1" 200 803 "http://mydomain.com/french/details.php?eid=127928&cid=18&fromval=1&frid=18" "Mozilla/5.0 (compatible; MSIE 9.0; Windows NT 6.0; Trident/5.0)"
于 2013-09-07T12:19:42.633 回答
1

根据您在此处的输入，您可以使用如下脚本：

#!/bin/bash

LOGFILE=/path/to/logfile

X=$(( 60 * 60 )) ## 1 Hour

function get_ts {
    DATE="${1%%\]*}"; DATE="${DATE##*\[}"; DATE=${DATE/:/ }; DATE=${DATE//\// }
    TS=$(date -d "$DATE" '+%s')
}

get_ts "$(tail -n 1 "$LOGFILE")"
LAST=$TS

while read -r LINE; do
    get_ts "$LINE"
    (( (LAST - TS) <= X )) && echo "$LINE"
done < "$LOGFILE"

将其保存到文件并更改 LOGFILE 的值，然后使用bash script.sh.

示例输出：

157.55.34.99 - - [06/Sep/2013:09:13:10 +0300] "GET /index.php HTTP/1.1" 200 16977 "-" "Mozilla/5.0 (compatible; bingbot/2.0; +http://www.bing.com/bingbot.htm)"
85.163.134.149 - - [06/Sep/2013:09:50:23 +0300] "GET /wap/wapicons/mnrwap.jpg HTTP/1.1" 200 1217 "http://mydomain.com/main.php" "Mozilla/5.0 (Linux; U; Android 4.1.2; en-gb; GT-I9082 Build/JZO54K) AppleWebKit/534.30 (KHTML, like Gecko) Version/4.0 Mobile Safari/534.30"
于 2013-09-06T18:24:20.627 回答