opencv - 寻找两个平面之间的透视变换

Question

我有一个从多个图像创建的点云。我从中提取了一个平面，它也在 3d 坐标系中，这意味着我有那个平面的平面方程。但在所有原始图像中，平面都没有正交视图，即平面不平行于观察平面。但是，由于我有平面的 3d 云，我想将它投影到 XY 平面上，即我想让平面平行于观察平面并从中创建图像。在 C++/OpenCV 中执行它的算法或函数是什么？

Answer 1

我不确定你到底想做什么，但这些可能会对你有所帮助，我用棋盘做了这个：

std::vector<cv::Point2f> not_a_rect_shape;  // In this vector you should save the x,y coordinates of your 3D rect  

// the not_a_rect_shapecoordinates are from you source frame 



// Define the destination image
            quad = cv::Mat::zeros(300, 220, CV_8UC3);  // the size is important, it depends on your application, I have to say that 300x220 isn't always the right one. you have to give more infomations!! 


// these will be the parallel plane vector of point 
quad_pts.push_back(cv::Point2f(0, 0));
            quad_pts.push_back(cv::Point2f(quad.cols, 0));
            quad_pts.push_back(cv::Point2f(quad.cols, quad.rows));
            quad_pts.push_back(cv::Point2f(0,quad.rows));


transformationMatrix= cv::getPerspectiveTransform(not_a_rect_shape, quad_pts);// this is you transformation matirx 

cv::warpPerspective(src, quad, transformationMatrix,quad.size(),CV_INTER_LINEAR,cv::BORDER_ISOLATED); // the flags could change 

现在四帧应该是你要找的！我希望它有帮助