我正在开发一个带有包含图像的选择列表的网页。我已经有了这个:
当我在列表中选择图像名称时,图像将显示在下面的 div 中。
<?php
// Create connection
$con=mysqli_connect("******","***","***","charts");
// Check connection
if (mysqli_connect_errno($con))
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
?>
<form method="post" action="index.php" id="nano" name="nano">
<p>
<select name="SelectBox" id="SelectBox" onchange="this.form.submit()">
<?php if($_POST['submitted'] == true){ ?>
<?php
$result = mysqli_query($con,"SELECT * FROM Nano WHERE IMAGE_NAME ='". $_POST['SelectBox']."'");
while($row = mysqli_fetch_array($result))
{ ?>
<option selected="selected" value="<?php echo $row['IMAGE_NAME'] ?>">
<?php echo $row['IMAGE_PARAMETER'] ?>
</option>
<?php } ?>
<?php echo $_POST['SelectBox']; ?></option>
<?php } else{ ?>
<?php
$result = mysqli_query($con,"SELECT TOP * FROM Nano");
while($row = mysqli_fetch_array($result))
{
?>
<option selected="selected" value="<?php echo $row['IMAGE_NAME'] ?>">
<?php echo $row['IMAGE_PARAMETER'] ?>
</option>
<?php
$var1 = $row['IMAGE_NAME']; ?>
<?php
}
?>
<?php } ?>
<option value="" disabled="disabled"> -------- </option>
<?php
$result = mysqli_query($con,"SELECT * FROM Nano");
while($row = mysqli_fetch_array($result))
{ $values[] = $row['IMAGE_NAME'];
?>
<option value="<?php echo $row['IMAGE_NAME'] ?>">
<?php echo $row['IMAGE_PARAMETER'] ?>
</option>
<?php }?>
</select>
<input type="hidden" name="submitted" id="submitted" value="true" />
</p>
<?php if($_POST['submitted'] == true){ ?>
<p><img src="Images\Nano\<?php echo $_POST['SelectBox']?>" width="953" height="600" /></p>
<?php }else { ?>
<p><img src="Images\Nano\<?php print_r($values[0]) ?>" width="953" height="600" /></p>
<?php } mysqli_close($con);?>
</form>
</div>
我希望当我在选择列表中向下移动时图片会改变,而不是当我在选择列表中单击它时。