出于测试目的,我复制了在phonegap 相机 API上找到的完整示例,并发出警报onPhotoDataSuccess
进行测试。在拍摄的第一张照片上,不会显示警报。但是,在第一次尝试后,警报将在照片保存后显示。
有什么建议吗?如果有不清楚的地方,我会很乐意更具体。
我在我的 Android Galaxy S3 上测试了下面的代码
<!DOCTYPE html>
<html>
<head>
<title>Capture Photo</title>
<script type="text/javascript" charset="utf-8" src="cordova.js"></script>
<script type="text/javascript" charset="utf-8">
var pictureSource; // picture source
var destinationType; // sets the format of returned value
// Wait for device API libraries to load
//
document.addEventListener("deviceready",onDeviceReady,false);
// device APIs are available
//
function onDeviceReady() {
pictureSource=navigator.camera.PictureSourceType;
destinationType=navigator.camera.DestinationType;
}
// Called when a photo is successfully retrieved
//
function onPhotoDataSuccess(imageData) {
// Uncomment to view the base64-encoded image data
// console.log(imageData);
// Get image handle
//
var smallImage = document.getElementById('smallImage');
// Unhide image elements
//
smallImage.style.display = 'block';
// Show the captured photo
// The inline CSS rules are used to resize the image
//
smallImage.src = "data:image/jpeg;base64," + imageData;
}
// Called when a photo is successfully retrieved
//
function onPhotoURISuccess(imageURI) {
// Uncomment to view the image file URI
// console.log(imageURI);
// Get image handle
//
var largeImage = document.getElementById('largeImage');
// Unhide image elements
//
largeImage.style.display = 'block';
// Show the captured photo
// The inline CSS rules are used to resize the image
//
largeImage.src = imageURI;
}
// A button will call this function
//
function capturePhoto() {
// Take picture using device camera and retrieve image as base64-encoded string
navigator.camera.getPicture(onPhotoDataSuccess, onFail, { quality: 50,
destinationType: destinationType.DATA_URL });
}
// A button will call this function
//
function capturePhotoEdit() {
// Take picture using device camera, allow edit, and retrieve image as base64-encoded string
navigator.camera.getPicture(onPhotoDataSuccess, onFail, { quality: 20, allowEdit: true,
destinationType: destinationType.DATA_URL });
}
// A button will call this function
//
function getPhoto(source) {
// Retrieve image file location from specified source
navigator.camera.getPicture(onPhotoURISuccess, onFail, { quality: 50,
destinationType: destinationType.FILE_URI,
sourceType: source });
}
// Called if something bad happens.
//
function onFail(message) {
alert('Failed because: ' + message);
}
</script>
</head>
<body>
<button onclick="capturePhoto();">Capture Photo</button> <br>
<button onclick="capturePhotoEdit();">Capture Editable Photo</button> <br>
<button onclick="getPhoto(pictureSource.PHOTOLIBRARY);">From Photo Library</button><br>
<button onclick="getPhoto(pictureSource.SAVEDPHOTOALBUM);">From Photo Album</button><br>
<img style="display:none;width:60px;height:60px;" id="smallImage" src="" />
<img style="display:none;" id="largeImage" src="" />
</body>
</html>
---------- 更新 1 ------------------
我已经在另一段代码上对其进行了测试:
(function () {
$scroller = $('.scroller'),
// Take a picture using the camera or select one from the library
takePicture = function (e) {
var options = {
quality: 45,
targetWidth: 1000,
targetHeight: 1000,
destinationType: Camera.DestinationType.FILE_URI,
encodingType: Camera.EncodingType.JPEG,
sourceType: Camera.PictureSourceType.CAMERA
};
navigator.camera.getPicture(
function (imageURI) {
console.log(imageURI);
alert('test');
$scroller.append('<img src="' + imageURI + '"/>');
},
function (message) {
// We typically get here because the use canceled the photo operation. Fail silently.
}, options);
return false;
};
$('.camera-btn').on('click', takePicture);
}());
这具有相同的效果。在第一次快照期间它什么也不做,但在第二次快照后显示图片。我还刚刚发现,在第二张照片之后显示的照片是我拍摄的第一张照片。似乎 getPicture 中的第一个参数不会在第一次快照时触发。这令人沮丧,因为 logcat 并没有真正向我展示任何可以使用的东西。
---------------- 更新 2 ----------------
我刚刚在 Phonegap Build 上尝试过,它可以工作。所以肯定跟插件有关系...