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在此应用程序中，当用户按下按钮时，将向服务器发送 url 请求，并且应用程序将接收一些相应的数据。

我的问题是我想完全从服务器接收数据，当连接完成接收数据时，更改视图并将接收到的数据传递给另一个视图。

数据转换后，我收到错误并且应用程序崩溃。

我尝试了这种方法，但不知道我该怎么做。
问题已解决，代码已编辑

 #import "ViewController.h"
@interface ViewController ()
//@property (nonatomic, strong) NSMutableData *responseData;

@end

@implementation ViewController
@synthesize responseData;
@synthesize myTableView;
- (void)viewDidLoad {
[super viewDidLoad];
NSLog(@"viewdidload");
}
- (void)didReceiveMemoryWarning
{
  [super didReceiveMemoryWarning];
}

- (void)connection:(NSURLConnection *)connection didReceiveResponse:(NSURLResponse *)response {

   NSLog(@"Response received From the server.");
  [self.responseData setLength:0];
}
  - (void)connection:(NSURLConnection *)connection didReceiveData:(NSData *)data {

  NSLog(@"appending data to the response object.");
  [self.responseData appendData:data];

}
 - (void)connection:(NSURLConnection *)connection didFailWithError:(NSError *)error {

   NSLog(@"didFailWithError");
   NSLog([NSString stringWithFormat:@"Connection failed: %@", [error description]]);
}

- (void)connectionDidFinishLoading:(NSURLConnection *)connection {
     NSLog(@"Loading data succeeded! Received %d bytes of data", 
       [self.responseData length]);
     //call the converter to convert the received 
     //Data to Json Packet and save to variable
     [self convertDataToJson];
      [self changePage];

 }
 -(void)changePage {
      resultsTableViewController *myTableView = [[resultsTableViewController  alloc]init];
       myTableView.modalTransitionStyle = UIModalTransitionStyleCoverVertical;
        myTableView=[myTableView init];
        [self presentViewController:myTableView animated:YES completion:NULL];

 }


-(void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
  {
   resultsTableViewController *mytable = [segue destinationViewController];
   NSMutableArray * response = self.responseArray;
   mytable.responseArray = response;

   }

- (IBAction)get:(id)sender {


  //making an instance of data query object and passing the word and dictionary selection to it.
   if ( ![[searchField text]isEqualToString:@""] )
   {
       word = @”test”
       [self makeRequestForWord:word withDictionaryName:@""];
       // NSData *query = [word dataUsingEncoding:NSUTF8StringEncoding];
  }
 }



-(void)makeRequestForWord:(NSString*)word withDictionaryName:(NSString*)dicSelect;
{

    //creating URL Request Object using given URL object.
    //It requests data using nsConnection

}


- (void)convertDataToJson
{
// some conversion and save into responseDATA
}

- (void)viewDidUnload {
   [super viewDidUnload];
}
@end

然后在与 segue 相关的功能中，我会将对象发送到下一个视图。

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1 回答 1

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您不应该在 connectionDidFinishLoading: 中显示视图控制器，因为您似乎为控制器设置了 segue - 它在那里崩溃，因为您尚未创建 myTable （在 .h 文件中声明它不会创建它）。segue 将创建控制器的实例，因此您应该在 connectionDidFinishLoading 中调用 performSegueWithIdentifier:sender:

- (void)connectionDidFinishLoading:(NSURLConnection *)connection {
     NSLog(@"Loading data succeeded! Received %d bytes of data", 
       [self.responseData length]);
     //call the converter to convert the received 
     //Data to Json Packet and save to variable
     [self convertDataToJson];

     [self performSegueWithIdentifier:@"MyIdentifier" sender:self];
 }
于 2013-09-05T15:52:58.583 回答