3

当我尝试添加此表时,我收到一个错误提示标识符无效。它已经困扰我太久了,所以我想我会问。

CREATE TABLE HORSE 
(  
horse_id numeric PRIMARY KEY,
horse_name character(30) not null,
horse_gender character(1) not null,
horse_height decimal not null,
horse_image character(40), 
CONSTRAINT horse_breed FOREIGN KEY (breed_id) REFERENCES breed(breed_id) 
);

错误信息是;

Error at Command Line:34 Column:37
Error report:
SQL Error: ORA-00904: "BREED_ID": invalid identifier
00904. 00000 -  "%s: invalid identifier"
*Cause:    
*Action:

感谢并抱歉问什么可能是一个非常愚蠢的问题。

4

1 回答 1

3

你需要breed_idHORSE表中

CREATE TABLE HORSE 
(  
horse_id numeric PRIMARY KEY,
horse_name character(30) not null,
horse_gender character(1) not null,
horse_height decimal not null,
horse_image character(40), 
breed_id numeric null
CONSTRAINT horse_breed FOREIGN KEY (breed_id) REFERENCES breed(breed_id) 
);
于 2013-09-05T06:53:52.717 回答