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当我试图从 python shell 打印函数时,它给了我这样的输出,这是正确的。
>> simplify(~A | (C & (~(B & ~C) | A))) >> ~A | C
我正在尝试使用 python 文件以这种方式做同样的事情
res = simplify(~A | (C & (~(B & ~C) | A))) print res
它给了我这个输出。
| ~A C