php - 在zend框架中获取URL id

Question

我需要 URL id 从 zend 框架 2 中的数据库中获取特定数据。这是我的控制器脚本：

$request = $this->getRequest();

    return new ViewModel(
            array('request' => $request));

这是视图：

echo $this->request;

我得到如下输出：

GET http://public.localhost.com:80/property/274 HTTP/1.1 Cookie: _ga=GA1.2.1235676771.1376588476; PHPSESSID=7bs59pfipit9eekd3tqmcocna3 Host: public.teamleads.com Connection: keep-alive Cache-Control: max-age=0 Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8 User-Agent: Mozilla/5.0 (Macintosh; Intel Mac OS X 10_8_4) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/29.0.1547.62 Safari/537.36 Accept-Encoding: gzip,deflate,sdch Accept-Language: en-US,en;q=0.8

但是，我只需要属性 id，即：274。我该怎么办？

Answer 1

只需使用 getParam() 方法：

// $request = $this->getRequest();
return new ViewModel(  
           array('property' => $this->getEvent()->getRouteMatch()->getParam('property'))
       );

在视图中：

echo $this->property;

Answer 2

return array ('property' => $this->params ('property'));

然后在视图中

echo $this->property

Answer 3

$requested = $this->getRequest(); $ad_id = $requested->getParam('ad_id'); //获取advertisingr_id $c_id = $requested->getParam('c_id');